MI 23M1PrelimQP (H2 PHYSICS P1)

Class Adm No Candidate Name: This document consists of 18 printed pages. [Turn over 2023 Preliminary Examinations Pre-University 3 H2 PHYSICS 9749/1 Paper 1 Multiple Choice 21 September 1 hour Additional Materials: Multiple Choice Answer Sheet READ THESE INSTRUCTIONS FIRST Do not turn over this page until you are told to do so. Write in soft pencil. Do not use staples, paper clips, highlighters, glue or correction fluid. Write your name, class and admission number on the Answer Sheet in the spaces provided. There are thirty questions on this paper. Answer all questions. For each question there are four possible answers A, B, C and D. Choose the one you consider correct and record your choice in soft pencil on the separate OMR Answer Sheet. Read the instructions on the Answer Sheet very carefully. Each correct answer will score one mark. A mark will not be deducted for a wrong answer. Any working should be done in this booklet. The use of an approved scientific calculator is expected, where appropriate. H

2 Data speed of light in free space c = 3.00  108 m s–1 permeability of free space o = 4 10–7 H m–1 permittivity of free space o = 8.85  10–12 F m–1 = (1/(36))  10–9 F m–1 elementary charge e = 1.60  10–19 C the Planck constant h = 6.63  10–34 J s unified atomic mass constant u = 1.66  10–27 kg rest mass of electron me = 9.11  10–31 kg rest mass of proton mp = 1.67  10–27 kg molar gas constant R = 8.31 J K–1mol–1 the Avogadro constant NA = 6.02  1023mol–1 the Boltzmann constant k = 1.38  10–23 J K–1 gravitational constant G = 6.67  10–11 N m2 kg–2 acceleration of free fall g = 9.81 m s–2

3 [Turn over Formulae uniformly accelerated motion s = ut + at2 v2 = u2 + 2as work done on/by a gas W = p V hydrostatic pressure p =  g h gravitational potential φ = temperature T/K = T / °C + 273.15 pressure of an ideal gas p = 1 3 𝑁𝑚 𝑉 < 𝑐2 > mean kinetic energy of a molecule of an ideal gas E = displacement of particle in s.h.m. x = xo sin t velocity of particle in s.h.m. v = vo cost v =  electric current I = Anvq resistors in series R = R1 + R2 + … resistors in parallel = electric potential V = alternating current/voltage x = xo sin t magnetic flux density due to a long straight wire B = 𝜇𝑜𝐼 2𝜋𝑑 magnetic flux density due to a flat circular coil B = 𝜇𝑜𝑁𝐼 2𝑟 magnetic flux density due to a long solenoid B = onI radioactive decay x = x0exp(–t) decay constant,  = 𝑙𝑛2 𝑡1/2

4 1 P and R are coplanar vectors. If X = P – R, which diagram best represents vector X? A B C D R P R P X R P X R P X R P X

5 [Turn over 2 The following are graphs of various quantities plotted against time for an object dropped from a stationary balloon high in the atmosphere. Which of the following statements most accurately describes the graphs? A Graph 1 is acceleration against time and graph 3 is resultant force against time. B Graph 1 is acceleration against time and graph 4 is resultant force against time. C Graph 3 is acceleration against time and graph 1 is velocity against time. D Graph 3 is acceleration against time and graph 2 is velocity against time.

6 3 The force acting on a 3.0 kg mass varies with time as shown. The object is initially moving at a velocity of 0.50 m s−1 in the same direction as the force. time / s force / N 0 0.5 1.0 10 5 0 What is the speed of the mass after 1.0 s? A 2.5 m s−1 B 3.0 m s−1 C 5.0 m s−1 D 7.5 m s−1 4 A particle X has initial momentum p. It collides with a stationary particle Y. The particle X is deflected through angle θ and its momentum is pX. The particle Y moves off at angle α to the original direction of motion of particle X with momentum pY as shown.

7 [Turn over Which equation is a correct statement for momentum in this collision? A pX cosθ = pY cosα B pX sinθ = pY sinα C pX cosθ + pY cosα = 0 D p = pX sinθ + pY sinα 5 A simplified diagram below represents the trunk of a person bent forward, with the spine at an angle of 70o to the vertical. The back muscle exerts a tension T and makes an angle of 8.0o to the spine. The weight of the person’s trunk which is 400 N, acts at the point along the spine where the back muscle is attached. weight of trunk: 400N tension T pivot at hip joint 70o 8.0o

8 What is the tension T in the back muscle? A 140 N B 380 N C 980 N D 2700 N 6 When a pebble of volume is hung on a spring balance, a reading of 8.0 N is obtained. The pebble is now totally immersed in a liquid of density . What is the reading on the spring balance now? A 1.6 N B 6.4 N C 8.0 N D 9.6 N 7 A trolley of mass 600 kg initially at point P on a slope, at height of 80 m above ground level, as shown. The trolley is released from rest and moves along the slope, reaches a speed of 12.0 m s−1 at point Q, at height h above the ground level. The total distance PQ moved by the trolley along the slope is 1.5 km. A constant resistive force of 200 N opposes the motion of the trolley on the slope. What is the value of h? A 3.5 m B 22 m C 29 m D 55 m

9 [Turn over 8 A boy is sitting on a playground turntable and is rotating with uniform angular velocity. The reaction force that the turntable exerts on the child is 160 N. The weight of the boy is 120 N. What is the acceleration of the boy? A 0.88 m s-2 B 3.3 m s-2 C 8.7 m s-2 D 84.3 m s-2 9 A space probe is used to measure the gravitational field strength g of a planet at a distance r from its centre. A graph of g against 1 𝑟2 for this planet produces a straight line graph through the origin. Which quantity can be determined from the gradient of the straight line graph? A the density of the planet B the radius of the planet C the volume of the planet D the mass of the planet 10 A satellite is in geostationary orbit above the Earth at a height of 36 000 km. The radius of the Earth is 6400 km. What is the orbital speed of the satellite? A 490 m s-1

10 B 2200 m s-1 C 2600 m s-1 D 3100 m s-1 11 A fixed mass of an ideal gas is at a pressure of 1.0 x 105 Pa. It has a temperature of 300 K and a volume of 0.010 m3. What is the total kinetic energy of the gas molecules after the volume is changed to 0.0050 m3 at constant temperature? A 500 J B 1000 J C 1500 J D 2000 J 12 The r.m.s. speed of the molecules of a gas at 295 K is decreased by 20 %. What is the new temperature of the gas? A – 84.4 °C B – 37.2 °C C 189 °C D 236 °C 13 75 g of potato chips is used as fuel to heat up a calorimeter that contains 2.00 x 10 3 g of water initially at 297 K. The temperature rises by 12 C. The heat capacity of the calorimeter is 200 J K 1 and the specific heat capacity of water is 4.18 J g 1 K 1. How much heat is released per gram of potato chip? A 1.37 kJ g-1 B 7.10 kJ g-1 C 100 kJ g-1 D 103 kJ g-1