2023 RI H2 Physics Prelims P1 Questions

RAFFLES INSTITUTION 2023 Preliminary Examination PHYSICS Higher 2 Paper 1 Multiple Choice 9749/01 September 2023 1 hour Additional Materials: Multiple Choice Answer Sheet READ THESE INSTRUCTIONS FIRST Write in soft pencil. Do not use staples, paper clips, glue or correction fluid. Write your name, class and index number on the Answer Sheet in the spaces provided. Shade your index number on the Answer Sheet. There are thirty questions on this paper. Answer all questions. For each question there are four possible answers A, B, C and D. Choose the one you consider correct and record your choice in soft pencil on the separate Answer Sheet. Read the instructions on the Answer Sheet very carefully. Each correct answer will score one mark. A mark will not be deducted for a wrong answer. Any rough working should be done in this booklet. The use of an approved scientific calculator is expected, where appropriate. This document consists of 16 printed pages.

2 © Raffles Institution Data speed of light in free space c = 81 3.00 10 m s −  permeability of free space 0 = 71 4 10 H m −−  permittivity of free space 0 = 12 1 8.85 10 F m −−  ( )( ) 91 1 36 10 F m −−  elementary charge e = 19 1.60 10 C −  the Planck constant h = 34 6.63 10 J s −  unified atomic mass constant u = 27 1.66 10 kg −  rest mass of electron me = 31 9.11 10 kg −  rest mass of proton mp = 27 1.67 10 kg −  molar gas constant R = 1 18.31 J K mol − − the Avogadro constant NA = 23 16.02 10 mol − the Boltzmann constant k = 23 11.38 10 J K − − gravitational constant G = 11 226.67 10 N m kg − − acceleration of free fall g = 29.81 m s− Formulae uniformly accelerated motion s = 21 2ut at+ 2v = 2 2u as+ work done on / by a gas W = pV hydrostatic pressure p = ρgh gravitational potential  = Gm r− temperature T / K = / C 273.15T + pressure of an ideal gas p = 21 3 Nm cV mean translational kinetic energy of an ideal gas molecule E = 3 2 kT displacement of particle in s.h.m. x = 0 sinxt  velocity of particle in s.h.m. v = 0 cosvt  22 0xx=  − electric current I = Anvq resistors in series R = 12 RR++ resistors in parallel 1/R = 1/R1 + 1/R2 + …. electric potential V = 4 Q r  alternating current/voltage x = 0 sinxt  magnetic flux density due to a long straight wire B = 0 2 d   I magnetic flux density due to a flat circular coil B = 0 2 N r  I magnetic flux density due to a long solenoid B = 0n I radioactive decay x = ( )0 expxt − decay constant  = 1/2 ln2 t

3 © Raffles Institution [Turn over 1 A vector F can be resolved into two perpendicular components F1 and F2. The angle between F and F2 is . How do the magnitudes of F1 and F2 change as  is increased from 0 to 90?