TMJC 2023 H2 Physics P4 MS

This document consists of 20 printed pages and 2 blank pages. CANDIDATE NAME CIVICS GROUP H2 Physics 9749/04 Paper 4 Practical 24 August 2023 2 hours 30 minutes Candidates answer on the Question Paper. No Additional Materials are required. READ THESE INSTRUCTIONS FIRST Write your name, class and index number in the spaces at the top of this page, page 9 and 17. Write in dark blue or black pen on both sides of the paper. You may use an HB pencil for any diagrams, graphs or rough working. Do not use staples, paper clips, glue or correction fluid. Answer ALL questions. You are allowed 1 hour to answer Questions 1 and 2; and you are allowed another 1 hour to answer Question 3. Question 4 is a question on the planning of an investigation and does not require apparatus. Write your answers in the space provided in the question paper. The use of an approved scientific calculator is expected, where appropriate. You may lose marks if you do not show your working or if you do not use appropriate units. Give details of the practical shift and laboratory where appropriate in the boxes provided. The number of marks is given in brackets [ ] at the end of each question or part question. For Examiner’s Use 1 /15 2 /7 3 /21 4 /12 Total /55 Shift Laboratory TAMPINES MERIDIAN JUNIOR COLLEGE JC2 PRELIMINARY EXAMINATION

2 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics 1 In this experiment you will be required to investigate the use of a combination of resistors in circuit analysis. Set up the apparatus as shown in Fig. 1.1. Resistor R represents the combined resistance of one to three 10.0 Ω resistors connected in parallel, series or a combination. (a) (i) Set R to be 10.0 Ω. (ii) Attach the crocodile clip K to M. Close the switch and record the voltmeter reading VM. VM = ………0.727 V ……………… (iii) Open the switch. Attach the crocodile clip K to N. Close the switch and record the voltmeter reading VN. VN = ………1.238 V ……………[1] (iv) Calculate the value of MN 11 VV− . MN 11 VV− = 11 0.727 1.238− = 0.568 V−1 MN 11 VV− = …………0.568 V−1…………….. 10.0 Ω V M N K Fig. 1.1 R • Correct dp and units for VM and VN. VN > VM

3 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics (v) Repeat steps (a)(ii) to (a)(iii) to obtain further sets of readings for VM and VN by varying R. [5] / R Ω M / VV N / VV 111 MN / VVV −− 11 / R −Ω 3.33 0.362 0.668 1.27 0.300 5.00 0.481 0.949 1.03 0.200 10.0 0.727 1.238 0.568 0.100 15.0 0.872 1.314 0.386 0.0667 20.0 0.979 1.364 0.288 0.0500 30.0 1.109 1.408 0.1915 0.0333 (b) Theory suggests that VM, VN and R are related by the expression MN 11 B CVVR−=+ where B and C are constants. Plot a suitable graph to determine B and C. Plot a graph of MN 11 VV− against 1 R . If the equation is valid, a straight line graph with gradient B and vertical intercept C will be obtained. Gradient = 4.96 B = 4.96 Ω V −1 Vertical intercept: Using the equation c = y – mx, C = 0.0453 C = 0.0453 V −1 B = ……4.96 Ω V−1………………… C = ……0.0453 V−1………………… [4] • Able to setup experiment to obtain 6 sets of readings [2]. - Deduct 1 mark if only 5 sets of readings. - Zero marks if 4 sets or less - Deduct 2 mark if trend is wrong. - Deduct 1 mark if 1st set is not recorded in table - Deduct 1 mark if V > 2 V - Deduct 1 mark if VN < VM (if mark not deducted earlier) - R = 0 Ω or other impossible R values are not considered as sets of readings • Correct quantity and units in the headers. [1] • Correct d.p. for raw data & s.f. of derived data [1] • Correct calculation for all derived data [1] • Correct linearisation. [1] • Gradient triangle is large enough, covering >1/2 of BFL. Correct read-off of gradient triangle coordinates. B calculated correctly. [1] • C calculated correctly. [1] • Correct s.f. and units for both B & C [1] - If C is not calculated, award this mark based on B alone

4 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics [3] 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 0.000 0.050 0.100 0.150 0.200 0.250 0.300 0.350 0.400 • Correct axis label with units and choice of scale so that graph occupies half graph paper. [1] • All data sets plotted accurately within half the smallest square. [1] • Best-fit line drawn correctly. [1] - Do not award if scatter is very poor - Do not award if anomalous point is not labelled clearly - Do not award if BFL based on 4 points or less Anomalous point 11 / R −Ω 111 MN / VVV −−

5 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics (c) By making suitable calculations, determine whether VM = VN can be achieved for this setup. MN 11 4.960 0.0453 109 B CVVR R R −=+ = + = −Ω VM = VN cannot be achieved from this setup since resistance cannot be negative. If positive R calculated, students may state - that VM = VN cannot be achieved using combinations of the resistors provided, or - that VM = VN can be achieved by using R of the calculated value / or R is positive …………………………………………………………………………………………………. …………………………………………………………….…………………………….. [2] [Total: 15] • Correct calculation of R [M1] - Do not award if wrong linearization • Correct conclusion based on R obtained. Explanation must be clear [A1]

6 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics 2 This experiment considers the forces on a wooden cylinder. (a) You have been provided with a wooden cylinder with a spring attached. The distance L between the centre of the hole at one end of the cylinder and the other end of the cylinder is shown in Fig. 2.1. Fig. 2.1 The length of the unstretched spring is S, as shown in Fig. 2.2. Fig. 2.2 Measure and record L and S. L1 = 59.0 cm L2 = 59.0 cm <L> = 59.0 cm 1st S = 5.3 cm 2nd S = 5.3 cm <S> = 5.3 cm L = ................................... S = ................................... [1] spring string wooden cylinder L • Correct dp and unit for both L and S. • 58.5 cm ≤ L ≤ 59.5 cm • Repeated readings • 4.8 cm ≤ s ≤ 5.8 cm

7 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics (b) Set up the apparatus as shown in Fig. 2.3. Fig. 2.3 Place the nail through the hole at the end of the wooden cylinder. Adjust the apparatus until the spring and the wooden strip are vertical and the wooden cylinder is horizontal. The distance x between the hole with the string and the hole with the nail is shown in Fig. 2.3. The length of the stretched spring is S 1. (i) Measure and record x and S1. x1 = 21.0 cm x2 = 21.0 cm <x> = 21.0 cm 1st S1 = 14.6 cm 2nd S1 = 14.6 cm <S1> = 14.6 cm x = ................................... S1 = ................................... [1] boss boss wooden strip stand spring wooden cylinder string head of nail x S1 rod of clamp bench clamp • Correct dp and unit for both x and S1 • Repeated readings for both x and S1. • 20.4 cm ≤ x ≤ 21.6 cm

8 Tampines Meridian Junior College 2023 JC2 Preliminary Examination H2 Physics (ii) Calculate e, where e = S1 – S. e = 14.6 – 5.3 = 9.3 cm e = ................................... [1] (c) Theory suggests that 2 MgLe kx= where g is 9.81 N kg−1, M is the mass of the wooden cylinder and k is the spring constant of the spring. Mass M is given on the card pasted on the