PHSS 2022 EYE 3NA Paper 2 QP

3NA EYE 2022 Marking Scheme & Marker’s report Qns Suggested Workings Marks Remarks 1 3.14 • ,  , 3.14 , 3.142− , 22 7− B2 – all 4 B1 – 3 correct 2a 32792 2 3 11=   B1 2b 2 11 22 p= = B1 3a 125 3 6.45 x= = B1 3b 2 2 yx z yx z yz x = = = M1 A1 4 5 3.6interest 25000 1 25000100 $4835.88 or $4840 = + −  = M1, M1 A1 M1 – correct value in formula M1- subtract 25000 5a cos152 cos 180 152 28 z z =−  = − = B1 5b ( ) ( ) ( ) ( ) ( ) ( ) 11 1 12.8 8.2 sin 36.7362 2 36.736sin 12.8 8.2 2 36.736 2 36.736sin or 180 sin 12.8 8.2 12.8 8.2 44.427 or 180 44.427 44.4 or 135.6 XYZ XYZ XYZ −−     = =     = −         =− =   M1 A1, A1 Need to put units for angle, else deduct 1 mark 6a   let total no. of balls be 13 9 2 13 22 2 13 13( 22) 2 11 286 26 shown x x x x x xx x x −− = − = −= = = M1 A1 Need to show 11 286x=

or 11 units ---------- blue + red 13 91 units ---------- 11 13 units ---------- 2 13 26 +  = M1 A1 Need to show 11 units (blue+red) 6b ( ) 26 9not red 26 17 26 P −= = B1 7a 9 11 123 10 1.23 10  = B1 7b 8 11 3 10 1.23 10 0.0024390 m =2.44 mm  =  = M1 A1 8a 3 2 9 29 3 2 33 2gradient 3 yx xy yx −= += =+ = M1 A1 Do not accept 3 s.f 8b ( )0,3 B1 8c ( ) Evidence: : subs. 3 and 1 into 3 2 3( 1) 2(3) 9 concept: Conclusion: 2, 1 does not lies on the line . LHS x y y x LHS RHS l = =− − − − =−  − M1 A1 Need to explain LHS not equal to RHS 9ai, 9aii ai: B1 aii: B1 – angle bisector B1 – point P Need to show the construction lines No mark if never mark out P

9b ( )7.8 0.1 cm ecf. B1 10 interior angle of polygon 90 360180 5 108 360 90 108 162 ext. angle of polygon 180 162 18 360no. of sides in polygon 18 A B C C C = =− = = − − = =− = = 20= M1 M1 M1 A1 Find both A and B interior Find C interior Either using ext. or int. formula Use int. formula needs to show algebra manipulation 11 ( ) 1 Evidence: 115 1.65 m tan 115 1.65tan 125 42.2 Concept: 40 42.2 Conclusion: Since 40 42 , Xing Qin claims is not correc t. She is unable to see the top of the flag unless FD FDFED GX FED − =− = −=  =     she tilted her head to at least 42.2 . M1 M1 M1 A1 Need to explain using the angle. OR Evidence: tan 40 125 125 tan 40 height of flag from ground 125 tan 40 1.65 106.5 m Concept: 106.5 m 115 m Conclusion: Since 106.5 m 115 m, Xing Qin claims is no t correct. She could only see up to 106.5 m f FD FD = = =  + =   rom the ground if she tilted her head to 40 .