2019 A level H1 Math Solutions - students (SAJC)
Uploaded by KSKS · 26 December 2023
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Appendix 2 1 Solution Template for 2019 A-level Examination Subject: H1 Mathematics ; Paper: 01 Questi on Suggested Solutions 1 Let $A, $B and $C be the price of Style A television, Style B television and Style C television respectively. 22 16 8 96480 (1) 22 16 3120 (2) 2 2 2 13260 (3) Using GC, 1800 2280 2550 The price of a Style B television is $2280. A B C AB A B C A B C + + = − − = − + + = − = = = 2(i) Using GC, when 0, 0.67721 the coordinates of is ( 0.677,0) yx A = =− − 2(ii) 4 3x=−
Appendix 2 2 2(iii) when 0, ln 4 the coordinates of is (0,ln 4) d3 1d 3 4 when 0, d 7 7 , hence gradient of tangent at is .d 4 4 7Equation of tangent at is ln 4 4 xy B y xx x y Bx B y x == =+ + = = = + 3(i) 2 2 2 6 3 (1) 11 9 (2) (1) (2) 2 5 12 0 ( 4)(2 3) 0 34 or 2 substitute 4 to (2) 11(4) 9 53 3substitute to (2)2 3 1511 9 22 3 154, 53 or , 22 y x x yx xx xx x x y x y x y x y = + − → = + → − − − = − + = = − = = + = =− = − + =− = = =− =−
Appendix 2 3 3(ii) 2 2 2 6 3 11 9 2 5 12 0 ( 4)(2 3) 0 x x x xx xx + − + − − − + 3 42 x− 4(i) 4 4 5 5 1Let (2 3 )(2 3 ) d 4(2 3 ) ( 3)d 12 (2 3 ) yx x y xx x − − = = −− =− − − = −
Appendix 2 4 4(ii) 2 2 3Let 2 94 12 d9 4d 4, 9 yx x yx x y xx pq =− = − + =− = =− 4(iii) ( ) 1 22 0 132 0 2 2 2 2 e d e232 1 e 123 2 2 11 e 62 11 1 6 2e x x xx x x − − − − +− = + − − = + + − =+ =+ 5(i) Initially, i.e. when t = 0, P = 0, Hence 00 1.5 0.6 0.6 k k = − =
Appendix 2 5 5(ii) 5(iii) Using GC, when t = 6, P = 6.2344 6.23 5(iv) Using GC, 3 d 0.821d t P t = =
Appendix 2 6 5(v) ( )( ) 32 2 2 2 2 2 2 2 2 10 25 10 d 3 20 25d dAt stationary point on the graph, 0d 3 20 25 0 5 3 5 0 55 or 3 d 6 20d when 5, d 6(5) 20 10 0,d 5 gives a minimum point on the graph . 5when , 3 d d C t t t C ttt C t tt tt t C tt t C t t t C t = − + + = − + = − + = − − = = =− = = − = = = = 56 20 10 0,3 5 gives a maximum point on the graph .3t − =− =
Appendix 2 7 5(vi) 5(vii) 6 32 0 Using GC, ( 10 25 10) d 114 The total cost incurred by Mr Tan over 6 years is $114000 t t t t− + + = (0, 10) x (5, 10) (6, 16) x , 28.5) C
Appendix 2 8 6(i) Group EI as 1 unit, total permutation of 8 units = 8! Permutate the unit consisting of EI = 2! No. of ways = 8! 2! 80640 = (ii) 9 4 7 4 No. of ways of choosing 4 letters without restriction = No. of ways of choosing 4 letters with no vowel = No. of ways with at least 1 vowel chosen No. of ways of choosing 4 letters without rest C C 97 44 riction No. of ways of choosing 4 letters with no vowel = 91 waysCC − −= 7(i) Let be the number of members in the sal es team that receive bonus out of 8. ~ B(8,0.32) P( 4) 0.15694 0.157 X X X = = (ii) P( 5) 1 P( 4) 0.074964 0.0750XX = − = (iii) ( ) ( ) Mean =E = 8(0.32) = 2.56 Variance = Var =8(0.32)(1 0.32)
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