2024 JPJC Chapter 11 Maclaurin Series and Binomial Expansion
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Text from the first pagesJurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 1 Chapter 11: Maclaurin’s Series & Binomial Expansions Content Outline standard series expansion of (1 )nx for any rational n, ex, sinx, cosx and ln(1 )x derivation of the first few terms of the Maclaurin’s series by – repeated differentiation, e.g. secx – repeated implicit differentiation, e.g. 3 2 22y y y x x – using standard series, e.g. e cos 2xx, 1ln1xx range of values of x for which a standard series converges concept of “approximation” small angle approximations: sinx x, 21cos 12x x , tanx x Exclude derivation of the general term of the series. References Websites https://www.h2maths.site/ Books (1) Ho Soo Thong, Tay Yong Chiang & Koh Khee Meng, “College Mathematics Syllabus C Volume 1”, Pan Pacific Publications, Call Number: HO510 (2) Pure Mathematics by Alan Sherlock, Elizabeth Roebuck, Timothy Heneage, Shirley Beck: Chapter 16 (3) Pure Mathematics 2 by L Bostock, S Chandler: Chapter 5 Pre-requisites: (1) Differentiation techniques including implicit differentiation (Chapter 6) (2) O level knowledge: Binomial Theorem, Sine Rule, Cosine Rule, Inequalities
Jurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 2 1. Introduction A power series in x is a series of ascending powers of x of the form 2 3 0 1 2 3f ( ) ... ... n nx a a x a x a x a x where ...,,...,,,, 3210 naaaaa are constants. Note that a polynomial is a subset of a power series, as a polynomial has only finite number of terms with positive integer powers. Examples of Power Series: 2 4x , 25 4x x , 33 5x x , 4 3 21 5 102x x x x , 1 2 3(1 ) 1 .... , 1x x x x x Example of Non-power Series: 3 2 24 7x xx Reason: The second term contains a _____________________ of x, and the third term contains a ______________________ for x. In this chapter, we shall learn to approximate a function by using polynomials. 2. Maclaurin’s Series Key Result: ( ) 2 3f (0) f (0) f (0)f ( ) f (0) f (0) ... ...2! 3! ! n n'' '''x x x x x n Note that ! 1 2 3 ... ( 1)r r r Remarks: (1) The above formula is given in the formula list MF26 as 2 ( )f ( ) f (0) f (0) f (0) ... f (0) ...2! ! n nx xx x '' n (2) The proof is in the Appendix. Example 1 Find the Maclaurin’s expansion for f(x) =ex up to and including the term in4x . Solution: f(x) = ex f '( )x = f ''( )x = f '''( )x = f (4)(x) = f(0) = f '(0)= f ''(0)= f '''(0)= f(4)(0) = Therefore, f ( )x 2 3 4 1 2 6 24 x x xx
Jurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 3 Remark: The Maclaurin’s series may be used for approximations. In general, an approximation becomes better when more terms of the Maclaurin’s series of f ( )x are included as illustrated below. Let ( )np x denote a polynomial of up to degree n. By successively differentiating ex , we find the Maclaurin’s series expansion of ex as a polynomial of (i) degree 0, 0( )p x , (ii) degree 1, 1( )p x , (iii) degree 2, 2( )p x , (iv) degree 3, 3( )p x . Let f ( ) exx f (0) 1 f ( ) exx f '(0) 1 f ( ) exx f ''(0) 1 f ( ) exx f '''(0) 1 From MF26, 2 3 f ( ) f (0) f '(0) f "(0) f (0)2! 3! x xx x 2 3 2 3 e 1 (1) (1) (1)2! 3! 1 2 6 x x xx x xx (i) 0e ( )x p x (ii) 1e ( )x p x (iii) 2e ( )x p x (iv) 3e ( )x p x Question: Which of the above polynomials would give us the best approximation for ex ?
Jurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 4 We now use graphs to compare the accuracy of the approximations of ex made by these four polynomials. Compare the graph of exy and the graphs of the four polynomials. Note that the graphs of 1( )y p x, 2( )y p x and 3( )y p x are virtually indistinguishable from the graph of exy near 0x. So these polynomials are good approximations of ex for values of x which are close to 0. However, the farther x is from 0, the poorer these approximations become. For a larger interval of x from 0, the approximation made by ( )np x gets better as n gets larger. In other words, the approximation becomes better when the polynomial includes more terms of the Maclaurin’s series of ex. Thus, ________ give us the best approximation for ex. y x 0 1 2 1 5 4 3 2
Jurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 5 Example 2 Find the first 3 non-zero terms in the Maclaurin’s expansion for (i) f( x) = sin x (ii) y = ln (1 + x) Solution: (i) f( x) = sin x f(0) = f '( )x = f '(0)= f ''( )x = f ''(0)= f '''( )x = f '''(0)= f (4)(x) = f (4)(0) = f (5)(x) = f (5)(0) = Therefore, f ( )x 2 3 4 5 0 (1) (0) ( 1) (0) (1)2! 3! 4! 5! x x x xx 3 5 6 120 x xx (ii) y = f(x) = ln (1 + x) f(0) = f '( )x = f '(0)= f ''( )x = f ''(0)= f '''( )x = f '''(0)= Therefore, y = 2 3 0 (1) ( 1) (2)2! 3! x xx 2 3 2 3 x xx
Jurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 6 Example 3 Given that cos ln(1 )y x , prove that (i) d(1 ) sin ln(1 ) ,d yx xx (ii) 2 2 2 d d(1 ) (1 ) 0d d y yx x yx x . Obtain an equation relating 3 2 3 2 d d d, and d d d y y y x x x . Hence find Maclaurin’s series for y, up to and including the term in 3x . Solution (i) Let cos ln(1 )y x Then d d y x= d1 sin ln(1 )d yx xx (shown) (ii) Differentiate (i) w.r.t. x: 22 2 d d1 1 0d d y yx x yx x (shown) Note: y =cos ln(1 )x . Differentiate (ii) wrt x : 3 22 3 2 d d d1 3 1 2 0d d d y y yx xx x x When x = 0, y = 1, d d y x0, 2 2 d d y x 1 and 3 3 d d y x 3 By Maclaurin’s Series, 2 3 31 ...2! 3! x xy 2 3 1 2 2 x x
Jurong Pioneer Junior College H2 Mathematics (9758) JC2-2024 Chapter 11 Maclaurin Series and Binomial Expansion (Students’ version) / Pg 7 3. Standard Series Expansions The following are standard series expansions derived from the Maclaurin’s series (discussed in Section 2) and the ranges of values of x for which the expansions are valid. They are found in MF26 and may be quoted without proof unless their derivation is asked for. 2( 1) ( 1)...( 1)(1 ) 1 2! ! n r n n n n n rx nx x x r (| | < 1)x 2 3 e 1 2! 3! ! r x x x xx r (all x) 3 5 2 1 ( 1)sin 3! 5! (2 1)! r rx x xx x r (all x) 2 4 2 ( 1)cos 1 2! 4! (2 )! r rx x xx r (all x) 2 3 1 ( 1)ln(1 ) 2 3 r rx x xx x r ( 11 x ) Note that when we deal with the sum or product of standard Maclaurin’s series, the range of values of x for which the expansion is valid is the intersection of the ranges of values of x for which each standard Maclaurin’s series used is valid. Example 4 By using the standard series, expand e sinxy x as a series of ascending powers of x up to and including the term in x3. Solution e sinxy x 3
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