ACSBR 2023 4EXP Prelim MA P2 MS
Uploaded by nanothethenem · 17 February 2024
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Marking Scheme Secondary 4 Exp Mathematics 4052/2 Anglo-Chinese School (Barker Road) 1 (a)(i) 42.25 (ii) (b) (c) 2 (a)(i) In triangle CFD and triangle BFA, Angle CDF = angle BAF (angle in the same segment) Angle ABF = angle DCF (angle in the same segment) Angle CFD = angle BFA (Vert. opp angles) By AA similarity test, the triangles are similar. (ii) (b)(i) (ii) 3 (a) 160 (b) All 7 points plotted Smooth curve through plotted points.
Marking Scheme Secondary 4 Exp Mathematics 4052/2 Anglo-Chinese School (Barker Road) (c)(i) Drawing of tangent at t = 3 55.5 (ii) The micro organisms are increasing at rate of 55.5 per day after 3 days. (d) Drawing of line 4.6 4 (a)(i)(a) 28 (b) 37-24 =13 (a)(ii) 35 (a) (iii) 45 marks (a)(iv) Disagree. Test 1, 12.5% scored distinction, Test 2, 25 % scored distinction. High proportion of students scored distinction in Test 2. (b)(i) 56.1 (ii) 9.98 5 (a)
Marking Scheme Secondary 4 Exp Mathematics 4052/2 Anglo-Chinese School (Barker Road) (b) (c)(i) London Hotel £160=S$271.19 Berlin Hotel 160€=S$249.60 The hotel in London is more expensive because It costs more at S$271.19>a stay in Berlin Hotel at S$249.60. (ii) 6 (a)(i) (ii) (b)(i) (a) a-b (b) (c) (ii) (iii) The two triangles are similar.
Marking Scheme Secondary 4 Exp Mathematics 4052/2 Anglo-Chinese School (Barker Road) (iv) 7 (a)(i) (ii) (b) (c)(i) x = 14.32 or x = 1.68 (ii) x = 1.68 will make time taken to be negative for Tap B (d) 8 (a) (b)(i) (ii) (c)
Marking Scheme Secondary 4 Exp Mathematics 4052/2 Anglo-Chinese School (Barker Road) 9 (a) Moon Hub 42.90+(16.05x30)+(10.70x2) $(42.90+4.815+21.4)=$69.12 SingCom 56.61+(8.60x2) $(56.61+17.20)=$73.81 Hence Owen should use Moon Hub as it cost less at $69.12. (b) SingCom $(73.81+56.61+38.89) $(73.81+56.61+38.89)x0.85 =$143.91 MoonHub $(69.12+42.90+39.90) =$151.92 Since SingCom cost < MoonHub cost, choose Singcom. 20/7/2023
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