ACSBR 2023 4EXP Prelim MA P1 MS

Marking Scheme Secondary 4 Exp Mathematics 4052/1 Anglo-Chinese School (Barker Road) 1 2 (a) 51.910 (b) 52 3 4 (a) (b) 42 5 (a) (b) (c)(i) (ii) 6 (a)

Marking Scheme Secondary 4 Exp Mathematics 4052/1 Anglo-Chinese School (Barker Road) (b) 7 (a) (b) x = 4 (c) Since the minimum value =2 which is above the x axis, the graph will not pass through the x-axis. 8 (a) (b)(i) Angle ABC = 900. Since angle in a semi-circle is 900, it is possible to draw a circle through A, B and C with AC as the diameter. (ii) Radius = 10.25cm 9 (a) Evidence of construction marks for angle bisector at angle C. (b) Evidence of construction marks for perpendicular bisector of BC. (c)

Marking Scheme Secondary 4 Exp Mathematics 4052/1 Anglo-Chinese School (Barker Road) 10 11 12 13 (a) (b) 400 14 (a) (b)

Marking Scheme Secondary 4 Exp Mathematics 4052/1 Anglo-Chinese School (Barker Road) (c) E represents the number of adults and children ferried in the morning and afternoon from Monday to Saturday. d(i) (ii) F represents the amount of money collected in cents on a weekday morning and afternoon. 15 (a) (b)(i) 4,16,36 (ii) 3 16 Grad of XY is undefined and so the line is parallel to y-axis. x = 1 17 (a)(i) (b)(i) (ii) 18 In triangle BOC and EOF, ● Angle BOC = angle EOF = 600 (angle at the point, ABCD is a regular hexagon) ● BC=EF (ABCD is a regular hexagon, all sides equal) ● Angle BCO = angle EFO = 600 (equilateral triangle) ● By ASA congruency test, triangle BOC is congruent to triangle EOF.

Marking Scheme Secondary 4 Exp Mathematics 4052/1 Anglo-Chinese School (Barker Road) 19 (a)(i) (ii) n = 5 (b) 20 Angle OBD = 900– x (angle between the tangent and radius of a circle is a right angle). Angle BOD = 1800– 2(900– x) = 2x (base angles of an isosceles triangle, OB = OD, radii of the circle) Angle BCD = (angle at the centre is twice the angle at the circumference) =1800– x 21 (a)(i) 61.85 (b)(i) (b)(ii) (c) There is improvement in the performance of students as the mean mark of the students in the final year examination 63.7 marks is higher than the mean mark of the mid-year examination of 61.85 marks. More students passed the final year examination. 22 (a)(i) (ii) (b)

Marking Scheme Secondary 4 Exp Mathematics 4052/1 Anglo-Chinese School (Barker Road) 23 (a) 1 (b) 6 (c) 3 24 (a)(i) 2 m/s2 (ii) (iii) 45+98+24.5 = 167.5 m (b) 25 Area of ½ square =1 cm2 Area of sector Area of shaded region= cm2