ACSBR 2023 3EXP Math EYE P1 Solutions

Marking Scheme Secondary 3 Express Mathematics 4052 End-of-Year Examination Paper 1 2023 Anglo-Chinese School (Barker Road) 1 (a) 2 (a) or (b) © The nth term is , hence the value should always be an even number. 3 (a) 15.99 million = (b) 4 (a) (b) 5 (a) (b) 6 7 (a) (b) Minimum point: 8

Marking Scheme Secondary 3 Express Mathematics 4052 End-of-Year Examination Paper 1 2023 Anglo-Chinese School (Barker Road) 9 (a) (bi) (bii) Line drawn (allow for for both answers) 10 (a) (b) 11 Interior angle of B = 12 (a) The bars do not start from zero, making the proportion of number of students in Aesthetics Club seems double of those in Debate Club. (b) It will be easier to show the exact numbers of private buses using a line graph than a pictogram.

Marking Scheme Secondary 3 Express Mathematics 4052 End-of-Year Examination Paper 1 2023 Anglo-Chinese School (Barker Road) 13 (a) (b) Since , it will always be a multiple of 3. 14 (a) Since , by the Converse of Pythagora’s Theorem, angle ADB is a right angle. (b) AC = 10 cm (c) Largest angle = angle ACB = 126.9°

Marking Scheme Secondary 3 Express Mathematics 4052 End-of-Year Examination Paper 1 2023 Anglo-Chinese School (Barker Road) 15 (a) (bi) (bii) 16 (a) (b) 17 1st equation: 2nd equation: Show elimination or substitution method. Number of small boxes = 238 Number of big boxes = 105 18 (a) (b)