TMJC H2 Chp 6A 3D Vector Geometry (Lines) Learning Package 2024
Uploaded by KSKS · 28 September 2024
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Chapter 6A 3D Vector Geometry (Lines) TMJC 2024 Page 1 of 23 H2 Mathematics (9758) Chapter 6A 3D Vector Geometry (Lines) Core Concept Notes Success Criteria: Surface Learning Deep Learning Transfer Learning Interpret and find equations of lines in the form r = a + d (vector equation) or x a y b z c l m n − − −== (cartesian equation) Convert the equations from one form to another Determine the relationship (i.e. intersecting, parallel or skew) between two lines Explain that two lines are coplanar if they are intersecting or parallel Find the angle between two lines Find the point of intersection of two lines if they intersect Find the length of projection of a vector onto a given line Find the foot of the perpendicular and perpendicular distance from a point to a line Find the reflection of a point in a line Interpret given information in contextual question
Chapter 6A 3D Vector Geometry (Lines) TMJC 2024 Page 2 of 23 Pre Reading Look through the following 2 examples BEFORE the first Independent Learning module on Chapter 6A in SLS. 1. Using the grid, draw the following vectors, marking the points R1, R2, R3, R4 and R5. (a) 1 1 1OR OA =+ − (b) 2 12 1OR OA =+ − (c) 3 13 1OR OA =+ − (d) 4 10 1OR OA =+ − (e) 5 12 1OR OA =− − (i) Join the points R1, R2, R3, R4 and R5. What do they form? (A line segment) (ii) What is the geometrical representation of the following equation? 1 1OR OA =+ − , . Position vector of a point on the line that passes through point A and is parallel to 1 1 − . X 0 1 2 3 4 5 6 7 8 9 10 0 1 2 3 4 5 6 7 8 9 10 O X A X X X X 2R 1R 3R 4R 5R
Chapter 6A 3D Vector Geometry (Lines) TMJC 2024 Page 3 of 23 2. The position vector of any point from the line is given in the form r = ac bd + , where . (i) State 2 possible values of a b . Just provide the column vector of ANY point on the line. Possible values of a b are 0 3 6, , etc8 5 2 (ii) State 2 possible values of c d . What does d c represent? Possible values of c d are 11 or 11 − − . d c represents the gradient of the straight line. 0 1 2 3 4 5 6 7 8 9 10 0 1 2 3 4 5 6 7 8 9 10 O
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