MI 2024 PU3 H2 PHYSICS PRELIM P4 ANS
Uploaded by nomz · 9 October 2024
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Mark Scheme and Suggested Solutions This document consists of XX printed pages and X blank page. [Turn over 2024 Preliminary Exams Pre-University 3 H2 PHYSICS 9749 / 04 Paper 4 Practical 26 August Candidates answer on the Question Paper. 2 hours 30 minutes READ THESE INSTRUCTIONS FIRST Write your name, class and admission number in the spaces provided at the top of this page. Write in dark blue or black pen on both sides of the papers. You may use an HB pencil for any diagrams, graphs or rough working. Do not use staples, paper clips, glue or correction fluid. Answer all questions. Write your answers in the spaces provided in this question paper. The use of an approved scientific calculator is expected, where appropriate. You may lose marks if you do not show your working or if you do not use appropriate units. Give details of the practical shift and laboratory where appropriate in the boxes provided. At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. Shift Laboratory For Examiner’s Use 1 16 2 8 3 19 4 12 TOTAL / 55 H
2 1 This investigation considers the size of the hole needed in a salt shaker for the salt to flow at a suitable rate. (a) You have been provided with a beaker labelled P containing 100 g of salt as shown in Fig. 1.1. Fig. 1.1 (i) Measure and record the depth x of salt in beaker P using the vernier calipers. Zero error = 0.00 cm x1 = 2.18 cm , x2 = 2.20 cm x = 2.18+2.20 2 = 2.19 cm x = …………………………………. [1] (ii) State a significant source of error in your value of x. [1] (iii) Estimate the percentage uncertainty in your value of x. ∆x = (0.01 + 0.04 )cm ∆𝑥 𝑥 × 100% = 0.05 2.19 × 100% percentage uncertainty = 2.3 % percentage uncertainty = …………………………………. [1] (b) You have been provided with two cards. Each card has a hole of a different size. (i) Measure and record the diameter d of the smaller hole. d1 = 0.46 cm , d2 = 0.47 cm d = 0.46+0.47 2 = 0.47cm d = …………………………………. [1] (ii) Determine the area A of the smaller hole. A = π(0.47 2 )2 𝐴 = 0.173 𝑐𝑚2 = 0.17 cm2 A = …………………………………. [1] x beaker salt 2.19 cm (2 d.p.) It was difficult to level the salt evenly within the beaker OR It was difficult to ensure that the tail of the vernier calipers was perpendicular to the based of the beaker 2.3 % (2 s.f.) 0.47 cm (2 d.p.) 0.17 cm2 (2 s.f.) [1] zero error recorded and considered in calculation. correct d.p. of x; Repeated readings recorded; and correct unit of x [1] A reasonable source of error stated Absolute uncertainty in the range of 2mm to 5mm (1.s.f.). [-1] either percentage uncertainty mo
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