2023 GSS 3E EOY Math Express P1 Marking Scheme

Marking Scheme For 2023 Sec 3E Mathematics EOY Paper 1 Item Worked Solutions Marks Awarded Remarks 1 53 3 158 14%6 −7.8 B2 1m – at least 2 consecutive correct order 2 100 PRTI     99800 2.58 5 100 $12874.20   Total value 99800 12874.20 $112674.20   M1 A1 Correct simple interest working Total value (overall minus 1m if $112674.2 given) 3 46 0.07035 22.34 3.1 4.45 50 0.07 20 3 4 3.5 14 0.25       M1 A1 for at least 3 number corrected to 1 sig. fig. 4a 330 180 5.76 rad   B1 Accepts 51 6 or 11 6  4b 5 180 8 112.5    B1 5   22 22 2 (8 3) ( 6) 34 (8 3) ( 6) 34 6 34 25 36 39 n n n n or               M1 A2 Apply length of line formula correctly Both values of n found

Marking Scheme For 2023 Sec 3E Mathematics EOY Paper 1 6 38.5 141.5or    (1 d.p.) A2 Both values found 7 1 2 2 112 177 49 7 7 7 77 11 2 p p p p       M1 A1 Award M1 if either 1 2 277 or seen Accepts 3 2 8 Total Amount 7 3.136850 1 100 $8499.349649   Interest $8499.349649 $6850 $1649.35   M1 M1 A1 A1 awarded only if corrected to nearest cent 9a 3yx B1 9b 5xy B1 9c 2 2y x B1 10 2 2 2( 5) 9( 5) 0 5 2 9 5 0 ( 5)(2 1) 0 5 (not applicable) 1 2 a a xx xx x or x               M1 M1 A1 Sub x = −5 M1 awarded only if a value = 5 found. Factorised form or use of general formula Award A1 only if 1 2x seen No A1 awarded if 5x is not rejected OR Both answers written on answer line 11a 2 15 19x 2 34x 17x B1 No B1 if only 17 or other form of inequalities seen

Marking Scheme For 2023 Sec 3E Mathematics EOY Paper 1 11b No, because there are 7 prime numbers less than or equal to 17 (2, 3, 5, 7, 11, 13 and 17). M1 A1 students must list all the 7 prime numbers. 12a 4 5 B1 12b 16sin 20 53.1 ABC ABC     M1 A1 13a 2 0 3 6 66 12 6( ) 6 6 a b a aa a      M1 A1 Award M1 if 66a is seen. No M1 if 606ab or any other factors multiplied to 66a 13b 1 15 3 1 3 15 5 125 125 5 a a a      M1 A1 Award M1 if 5 1 3125 a  seen Not accepted 55a 5 0.2 a 14 (A) (common angle) (S) 12 3 9 (given) (A) 90 (given) By ASA congruence test, triangle is congruent to triangle CAB SAR AB AR ABC ARS ABC ARS           M2 A1 M1 for any 2 statements Conclusion with correct test chosen. Award if ‘  ’ sign used 15   2 22 22 22 33 9 9 9 9 9 18 9 9( ) 18( ) 9(23) 18(17) 99 xy x xy xy y x xy y x y xy              M1 A1 16a ( 5)(2 ) Subs 0, 10 10 (0 5)(2(0) ) 2 y x x b xy b b         B1 16b (5, 0) B1

Marking Scheme For 2023 Sec 3E Mathematics EOY Paper 1 16c ( 5)(2 ) 0 51 x x b x or x   