Bendemeer 2024 4E Prelim EMath P2 - MS

This document consists of 22 printed pages. [Turn over CANDIDATE NAME CLASS INDEX NUMBER ------------------------------------------------------------------------------------------------------------------------------------- ------------------------------------------------------------------------------------------------------------------------------------- READ THESE INSTRUCTIONS FIRST Write your name, class and register number on all the work you hand in. Write in dark blue or black pen. You may use an HB pencil for any diagrams or graphs. Do not use staples, paper clips, highlighters, glue or correction fluid. DO NOT WRITE ON ANY BARCODES. Answer all the questions. The number of marks is given in brackets [ ] at the end of each question or part question. If working is needed for any question, it must be shown with the answer. Omission of essential working will result in loss of marks. The total number of marks for this paper is 90. The use of an approved scientific calculator is expected, where appropriate. If the degree of accuracy is not specified in the question, and if the answer is not exact, give the answer to three significant figures. Give answers in degrees to one decimal place. For  , use either your calculator value or 3.142. FOR EXAMINER’S USE MATHEMATICS Paper 2 4052/02 21 August 2024 2 hours 15 minutes Candidates answer on the Question Paper. No additional materials are required. BENDEMEER SECONDARY SCHOOL 2024 PRELIMINARY EXAMINATION SECONDARY 4 EXPRESS / 5 NORMAL (ACADEMIC) 90 MARKING SCHEME

2 4052/02/Sec 4E5N(A)/Prelim/BDMS 2024 MATHEMATICAL FORMULAE Compound Interest Total amount = P n r      + 1001 Mensuration Curved surface area of cone = rl Surface area of a sphere = 4  r2 Volume of a cone = hr 2 3 1 Volume of sphere = 3 3 4 r Area of triangle ABC = Cabsin2 1 Arc length = radiansin is where, r Sector area = radiansin is where,2 1 2 r Trigonometry C c B b A a sinsinsin == Abccba cos2222 −+= Statistics Mean =   f fx Standard Deviation =        −     22 f fx f fx

3 4052/02/Sec 4E5N(A)/Prelim/BDMS 2024 [Turn Over 1 (a) Simplify ( 3𝑎−3 2𝑏2 4 1 2𝑏3 ) −2 and leave your answer in positive index notation. = ( 4 1 2𝑏3 3𝑎−3 2𝑏2 ) 2 ………………. M1 = 4𝑏6 9𝑎−3𝑏4 …………………. M1 = 4𝑎3𝑏2 9 ……………………. A1 Answer (a) __________________________ [3] (b) Simplify (𝑎−5𝑏)2 𝑎2−25𝑏2 ÷ 𝑎−5𝑏 5𝑏 . = (𝑎−5𝑏)2 (𝑎−5𝑏)(𝑎+5𝑏) × 5𝑏 𝑎−5𝑏 ………… M1 for (𝑎 − 5𝑏)(𝑎 + 5𝑏) = 5𝑏 𝑎+5𝑏 ……………………………… A1 Answer (b) __________________________