GMSS 4NA EM P1 Prelim 2024 Ans key
Uploaded by currymuncher · 15 October 2024
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Candidate Name ANSWER KEY Class Index Number MATHEMATICS (SYLLABUS A) Paper 1 4045 / 01 4 Normal (Academic) Candidates answer on the Question Paper. 2 hours Setter: Ms Tan Kai Wei Monday, 5 August 2024 READ THESE INSTRUCTIONS FIRST Write your class, index number and name in the spaces at the top of this page. Write in dark blue or black pen. You may use a pencil for any diagrams or graphs. Do not use staples, paper clips, highlighters, glue or correction fluid. Answer all the questions. The number of marks is given in brackets [ ] at the end of each question or part question. If working is needed for any question it must be shown with the answer. Omission of essential working will result in loss of marks. The total of the marks for this paper is 70. The use of an approved scientific calculator is expected, where appropriate. If the degree of accuracy is not specified in the question and if the answer is not exact, give the answer to three significant figures. Give answers in degrees to one decimal place. For π, use either your calculator value or 3.142, unless the question requires the answer in terms of π. For Examiner’s Use This document consists of 18 printed pages and 2 blank pages. Geylang Methodist School (Secondary) Preliminary Examination 2024 70 [Turn Over
GMS(S)/EMath/P1/PRELIM2024/4N(A) 2 [Turn Over Mathematical Formulae Compound Interest n rP 1001amount Total Mensuration rl cone a of area Surface Curved 24 sphere a of area Surface r hr 2 3 1 cone a of Volume 3 3 4 sphere a of Volume r CabABC sin2 1 triangleof Area radiansin is where,length Arc r radiansin is where,2 1 areaSector 2 r Trigonometry C c B b A a sinsinsin Abccba cos2222 Statistics f fx Mean 22 deviation Standard f fx f fx
GMS(S)/EMath/P1/PRELIM2024/4N(A) 3 [Turn Over Answer all the questions. 1 (a) Write 0.005 625 819 correct to 4 significant figures. Ans: 0.005626 (4sf) Answer ……………..…………. [1] (b) Express 338 as a percentage. Ans: 337.5% Answer ……………..………… % [1] 2 Find the smallest integer satisfying the inequality 3 17x . 3 17x 25 3x [M1] Smallest integer = 5 [A1] Answer ……………..…………. [2] 3 (a) sin 0.6x Given that x is an obtuse angle, find x. sin 0.6x 1sin 0.6x 36.9 or 143.1 (1dp) Since x is an obtuse angle, 143.1x . [B1] Answer x = …………..…………. [1] (b) cos135 cos y Given that y is an acute angle, find y. 180 135y 45 y = 45 [B1] Answer y = …………..…………. [1]
GMS(S)/EMath/P1/PRELIM2024/4N(A) 4 [Turn Over 4 [B1 for 2 correct lines drawn x2] Draw an enlargement of thi
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