2024 EJC J2 H1 PRELIM P1-2 Answer

©EJC 2024 8867/J2H1PRELIM/2024 EUNOIA JUNIOR COLLEGE JC2 Preliminary Examination 2024 8867 PHYSICS MARK SCHEME Paper 1 – Multiple Choice Questions Question Key Question Key Question Key 1 D 11 A 21 D 2 B 12 B 22 A 3 B 13 D 23 D 4 C 14 C 24 A 5 B 15 B 25 D 6 B 16 D 26 C 7 D 17 D 27 B 8 A 18 C 28 C 9 B 19 D 29 C 10 A 20 B 30 C

2 ©EJC 2024 8867/J2H1PRELIM/2024 1 Answer: D 2 units of energy = J =(kg m s )(m)  -2 2 -3 kg m s munits of intensity = m s kg s 2 Answer: B 2 0.0534 2 1 0.1 1268 5.0 25 0.0947 0.0534 0.0947 0.005057 0.005 (5.3 0.5) 10 m LR A RA L R D L R D L                               3 Answer: B Option A gives a radius of 6 cm Option B gives a radius of 13 cm Option C gives a radius of 29 cm Option D gives a radius of 62 cm B is the most sensible answer. Intensity = Power/Area = Rate of Work done/Area

3 ©EJC 2024 8867/J2H1PRELIM/2024 4 Answer: C 2 2 1 gts  on earth, 2'62 1 tgs      on moon  22 6' tt  and tt 6' 5 Answer: B As the projectile rises, the vertical component of the velocity of the projectile decreases to zero at the top of its trajectory, then increases to its initial value in the downward direction as the projectile comes back down to its original launch level. The projectile’s horizontal velocity component, however, remains constant throughout. Speed v is the magnitude of velocity, which is a vector sum of the horizontal and vertical component. The graph for v should be a curve that decreases to a non-zero value (when projectile is at its highest), then increases back to its initial value u. 6 Answer: B Change in momentum,     1 1 2 5 2 2 12 9.0kgms p Area under F t graph          1 ( 2.0) 9.0 2.0( 2.0) 9.02.0 2 6.5 p m v v v ms         

4 ©EJC 2024 8867/J2H1PRELIM/2024 7 Answer: D 8 8 To find the force on X by Y, consider X: ( )8 7 8 To find the force on Y by Z, consider Z: 4 4 ( )8 1 2 By Newton's 3rd Law: 7 8Ratio: 1 2 7 4 XY XY ZY ZY ZY YZ XY YY F ma Fa m F F ma FF F m m F F ma FF m m F F F FF F F              8 Answer: A Total momentum of the system is conserved because no external force acts on the gliders. Option B: Before collision, total momentum of the system is zero. Option C: Kinetic energy is not conserved when both magnets are rest. Option D: Both magnets have the same mass, the magnetic force on each magnet is the same, no friction on track, total kinetic energy of the system is conserved before and after collision.

5 ©EJC 2024 8867/J2H1PRELIM/2024 9 Answer: B Using relative speed of approach = relative speed of separation Eliminate Option A: 5-(-2) = 5-2 (false) Eliminate Option C: 5-(-2) = 4-4 (false) Using logical deduction, eliminate D as after collision, the speed of the la