2024_HYSS_Prelim_Sec 4G2_Math_QP_P2

[Turn Over HUA YI SECONDARY SCHOOL PRELIMINARY EXAM 2024 4-G2 NAME CLASS INDEX NUMBER MATHEMATICS 4045/02 PAPER 2 (XX) 05 August 2024 2 hours Candidates answer on the Question Paper. READ THESE INSTRUCTIONS FIRST Write your Name, Class and Index Number in the spaces provided at the top of this page. Write in dark blue or black pen. You may use an HB pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. Section A Answer all questions. Section B Answer one question. The number of marks is given in brackets [ ] at the end of each question or part question. If working is needed for any question it must be shown with the answer. Omission of essential working will result in loss of marks. The total of the marks for this paper is 70. The use of an approved scientific calculator is expected, where appropriate. If the degree of accuracy is not specified in the question, and if the answer is not exact, give the answer to three significant figures. Give your answers in degrees to one decimal place. For  , use either your calculator value, or 3.142. For Examiner’s Use This document consists of 19 printed pages and 1 blank page. © HYSS 2024 No part of this document may be reproduced in any form or transmitted in any form or by any means without the prior permission of Hua Yi Secondary School. Setter: Ms Shirlynn Khoo 70

2 2024_4-G2_PRELIMS_ MATHEMATICS _PAPER 2 [Turn Over Mathematical Formulae Compound interest Total amount = n rP      + 1001 Mensuration Curved surface area of a cone = lr Surface area of a sphere = 24 r Volume of a cone = Volume of a sphere = Area of triangle = ABC Arc length = , where is in radians Sector area = , where  is in radians Trigonometry C c B b A a sinsinsin == Abccba cos2222 −+= Statistics Mean = f fx   Standard deviation = 22        −  f fx f fx hr 2 3 1 3 3 4 r Cabsin2 1 r  2 2 1 r

3 2024_4-G2_PRELIMS_ MATHEMATICS _PAPER 2 [Turn Over Section A (62 marks) Answer all the questions in this section. 1 Written as the product of its prime factors, 22396 2 3 11=   . (a) (i) Explain why 396 is not a perfect square. ………………………………………………………………………….. ………………………………………………………………………….. [1] (ii) Find the smallest positive integer value of k such that 396k is a perfect cube. Answer k = …….…………………… [1] (b) (i) Express 2100 as the product of its prime factors. Answer …….……………………….. [2] (ii) Hence find the highest common factor of 396 and 2100. Answer …….……………………….. [1]

4 2024_4-G2_PRELIMS_ MATHEMATICS _PAPER 2