AMKSS_Prelim_2024_AMath_P2_MS
Uploaded by ilovePAP · 18 November 2024
Preview
2024 AMKSS 4E5N Prelim AMP2 Marking Scheme Qn Solution Marks 1 1 2 100 10 24 0 10 10 10 24 0 x x x x Let 10xy 2 10 24 0 12 2 0 y y y y 12y or 2y 10 12 rejected x 10 2x lg10 lg 2x lg 2x B1 (correct quadratic) M1 (factorise or quadratic formula) A1 (reject 10 12x , do not accept if reject 12y ) A1 2 Let 3f 3 5 2x x x 3 f 1 3 1 5 1 2 0 By factor theorem, 1x is a factor of 33 5 2x x . 3 23 5 2 1 3 2x x x x Ax Comparing coefficient of x, 5 2 3 A A 21 3 3 2 0x x x 1x or 2 3 3 4 3 2 2 3x 3 33 6x B1 M1 (or long division: must see 23x ) M1 (factors equate to 0) A1 (for 1x ) A1 (for exact values) 3(a) 1 1 2 2 1 2 1 4 1 d 1 4 1 1 1 4 1 4d 2 4 1 4 1 2 1 4 1 2 2 4 1 6 1 4 1 y x x y x x xx x x x x x x x x M1 (for chain rule), M1 (product rule) M1 (factorise or combine to single fraction) A1
Qn Solution Marks 3(b) 66 2 2 66 6 2 2 2 6 1 d 1 4 1 4 1 6 1 d d 1 4 1 4 1 4 1 x x x x x x x x x x x x 6 1 266 2 2 2 6 6 2 2 6 2 4 16 d 1 4 1 14 1 42 1 4 1 d 1 4 16 24 1 4 6 16 1 4 6 1 21 d 64 1 4 2 12 1 4 2 1 2 53 6 xx x x x x x x x x x x x x x M1 (using (i)) M1 (integrate their 4 1 q x correctly) A1 (correct 6 2 d 4 1 x x x including 1 6 ) M1 (substitute correct values in correct order) A1 4(a) 2x or 3x 2 3 0x x 2 2 6 0 3 3 18 0 x x x x 3p 18q M1 (accept 2 3 0x x ; 3 2 3y x x ) A1 A1 4(b) (i) 2 2 2 2 2 1 3 3 1 1 0 1 4 3 1 0 2 1 12 12 0 10 11 0 11 1 0 qx x x q x q x q q q q q q q q q q 11q or 1q M1 (eliminate x or y) M1 (correct D and = 0) M1 (factorise or quadratic formula) A1 4(b) (ii) 2 2 2 3 12 12 0 4 4 0 2 0 2 21 2, 21 x x x x x x y R M1 (factorise or quadratic formula A1 (correct x) A1 (correct y)
Qn Solution Marks 5(a) (i) T 2.2 5.0 7.8 10 12.8 lg t 0.146 0.283 0.420 0.526 0.662 B2 (minus 1 for each incorrect point; minus 1 if axes not labelled) 5(a) (ii) (a) When 0T lg 0.04 1.10 (accept 1.07 to 1.13) t t M1 (equate vertical intercept to lg t) A1 (both marks only given if graph is extended to find lg t -intercept) 5(a) (ii) (b) lg lg lg 1.064 lg lg lg 1.064 kT t a t a kT Gradient = 0.0487 lg 1.064 0.0487 0.0487 lg 1.064 1.807611629 1.81 acce
Content continues in the PDF.
Related notes
- Amath NotesNotes/Practices · 2026
- A Math MindmapsNotes/Practices
- SPS AM Prelim PapersExam Papers · 2021
- SPS AM Prelim AnsExam Papers · 2021
- Secondary School Additional Mathematics Notes Compilation-15Notes/Practices
- Secondary School Additional Mathematics Notes Compilation-14Notes/Practices

