XMSS 2024 AM Prelim (P1) Mark Scheme

This document consists of 18 printed pages. [Turn over XINMIN SECONDARY SCHOOL SEKOLAH MENENGAH XINMIN Preliminary Examination 2024 CANDIDATE NAME Mark Scheme [Draft 3] CLASS INDEX NUMBER ADDITIONAL MATHEMATICS Paper 1 Secondary 4 Express Setter : Mr Johnson Chua Vetter : Ms Low Yan Jin Moderator : Ms Pang Hui Chin Candidates answer on the Question Paper. No Additional Materials are required. 4049/01 23 August 2024 2 hour 15 minutes READ THESE INSTRUCTIONS FIRST Write your name, register number and class in the spaces at the top of this page. Write in dark blue or black pen. You may use an HB pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. Answer all the questions. Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place in the case of angles in degrees, unless a different level of accuracy is specified in the question. The use of an approved scientific calculator is expected, where appropriate. You are reminded of the need for clear presentation in your answers. The number of marks is given in brackets [ ] at the end of each question or part question. The total number of marks for this paper is 90. Errors Qn No. Errors Qn No. Accuracy Simplification Brackets Units Geometry Marks Awarded Presentation Marks Penalised For Examiner’s Use 90 Parent’s/Guardian’s Signature:

2 Mathematical Formulae 1. ALGEBRA Quadratic Equation For the quadratic equation ax 2 + bx + c = 0, 2 4 2 b b acx a −  −= Binomial Expansion ( ) 1 2 2 12 n n n n n r r nn n na b a a b a b a b b r − − −     + = + + + + + +           , where n is a positive integer and ( ) ! ( 1)...( 1) ! ! ! n n n n n r r n r r r  − − +== − 2. TRIGONOMETRY Identities sin 2 A + cos 2 A = 1 sec 2 A = 1 + tan 2 A cosec 2 A = 1 + cot 2 A sin (A ± B) = sin A cos B ± cos A sin B cos (A ± B) = cos A cos B  sin A sin B tan ( A ± B ) = tan tan 1 tan tan AB AB  sin 2A = 2 sin A cos A cos 2A = cos2 A – sin2 A = 2cos2 A – 1 = 1 – 2 sin2 A tan 2A = 2 2 tan 1 tan A A− Formulae for  ABC sin sin sin a b c A B C== a 2 = b 2 + c 2 − 2bc cos A  = 2 1 bc sin A

3 [Turn over 1 A triangle has a base of length ( )6 2 7+ cm and an area of ( )17 7 7+ cm2. Find, without using a calculator, the perpendicular height to the base of the triangle, in cm, in the form ( )7ab+ , where a and b are integers. [3] 2 Solve the equation 51 xx− + = . [4] ( ) ( ) ( ) ( )( ) ( )( ) 2 1 6 2 7 17 7 7 --- [M1]2 2 17 7 7 6 2 7 17 7 7 3 7 --- [M1] 3 7 3 7 51 17 7 21 7 49 37 2 4 7 2 1 2 7 -- h h h h h h +  = + + = + +− = +− − + −= − += =+ -[A1] Alternative ( )( ) ( )( ) 34 14 7 6 2 7 --- [M1] 6 2 7 6 2 7