RVHS Prelim P4 Soln
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River Valley High School JC 2 H2 Chemistry 9729 2020 Prelim Practical Examination Suggested Solution RIVER VALLEY HIGH SCHOOL JC 2 PRELIM PRACTICAL EXAMINATION H2 CHEMISTRY 9729 PAPER 4 SUGGESTED SOLUTION 1 (a) Ksp = [Ca2+][IO3]2 (b) Results titration 1 2 final burette reading / cm3 19.60 39.20 initial burette reading/ cm3 0.00 19.60 volume of FA 2 used / cm3 19.60 19.60 (c) (i) average volume of FA 2 used = 19.60 19.60 2 =19.60 cm3 VFA 2 = 19.60 cm3 (ii) amount of S2O32 = 19.600.100 1000 = 0.00196 mol IO3 3I2 6S2O32 amount of IO3 in 25.0 cm3 of FA 1 = 0.00196 6 = 3.267 104 = 3.27 104 mol amount of IO3 in 25.0 cm3 of FA 1 = 3.27 104 mol (iii) amount of dissolved IO3 in the mixture from (b) at equilibrium = 4 100.03.267 10 25.0 = 1.307 103 mol amount of IO3(aq) in the mixture = 1.307 103 mol
River Valley High School JC 2 H2 Chemistry 9729 2020 Prelim Practical Examination Suggested Solution (d) (i) amount of IO3 from KIO3 = 100.00.0100 1000 = 0.00100 mol amount of IO3 from dissolved Ca(IO3)2 = 1.307 103 0.00100 = 3.07 104 mol amount of IO3(aq) from dissolved Ca(IO3)2 = 3.07 104 mol (ii) amount of Ca2+ in mixture = 43.07 10 2 = 1.535 104 = 1.54 104 mol (to 3 s.f.) amount of Ca2+(aq) in the mixture = 1.54 104 mol (e) [Ca2+]eqm = 41.535 10 0.100 = 1.535 103 mol dm3 [IO3]eqm = 31.307 10 0.100 = 1.307 102 mol dm3 Ksp = [Ca2+][IO3]2 = (1.535 103)( 1.307 102)2 = 2.62 107 mol3 dm9 (to 3 s.f.) Ksp = 2.62 107 mol3 dm9 (f) FA 1 would be diluted/ [IO3] in FA 1 is lowered/ lower amount of IO3 in 25.0 cm3 of FA 1. This forms less I2 for reaction with S2O32. Therefore, the mean titre would be lower. (g) The student did not carry out the experiment at 25 °C. Hence, the position of equilibrium for Ca(IO3)2(s) Ca2+(aq) + 2IO3(aq) shifted to the left. OR When the student carried out the experiment, equilibrium has not been reached before filtering in (b) step 4. Hence, the [Ca2+] and [IO3] is lower.
River Valley High School JC 2 H2 Chemistry 9729 2020 Prelim Practical Examination Suggested Solution 2 (c) Results Shift 1 and timed practice Experiment VFA 5 / cm3 2HOV for solution A / cm3 VFA 6 / cm3 2HOV for solution B / cm3 t /s 1 t /s1 1 5.0 30.0 20.0 10.0 22.1 0.0425 2 10.0 25.0 20.0 10.0 11.1 0.0901 3 5.0 30.0 10.0 20.0 48.1 0.0208 Shift 2 Experiment VFA 5 / cm3 2HOV for solution A / cm3 VFA 6 / cm3 2HOV for solution B / cm3 t /s 1 t /s1 1 10.0 25.0 20.0 10.0 15.4 0.0649 2 20.0 15.0 20.0 10.0 8.0 0.125 3 10.0 25.0 10.0 20.0 28.3 0.0353 Shift 3 Experiment VFA 5 / cm3 2HOV for solution A / cm3 VFA 6 / cm3 2HOV for solution B / cm3 t /s 1 t /s1 1 10.0 25.0 20.0 7.0 11.8 0.0847 2
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