TMJC_2025_H2 Physics_P1_Soln

1 Tampines Meridian Junior College 2025 JC2 Preliminary Examination H2 Physics Tampines Meridian Junior College 2025 JC2 H2 Physics Preliminary Examination Paper 1 Suggested Solution 1 D 11 B 21 C 2 B 12 A 22 B 3 C 13 C 23 A 4 D 14 B 24 D 5 B 15 A 25 C 6 B 16 D 26 B 7 B 17 C 27 B 8 D 18 D 28 D 9 C 19 C 29 C 10 A 20 B 30 D Q1 Ans: D Q2 Ans: B Gradient of the graph started with maximum magnitude before slowing decreasing and becoming zero. Acceleration (given by gradient of V-t graph) of an object falling in the presence of air resistance will decreases until terminal velocity is reached and become zero. Thus option B is the answer. Q3 Ans: C To ensure rotational equilibrium, the line of action of the forces must pass through a single point. vbicycle relative to bus Vbicycle –vbus 3 N 4 N 5 N

Tampines Meridian Junior College 2025 JC2 Preliminary Examination H2 Physics Q4 Ans: D ( ) ( ) Let be tension in string sin (1) (2) (2) (1) sin sinsin T T mg ma Mg T Ma Mg mg Ma ma MmMg mgag M m M m    −= −= + − = + −−== ++ Q5 Ans: B Torque by 30 N couple = 30 (2)(0.065) = 3.9 N m (anti-clockwise) Torque by 25 N couple = 25 (2)(0.12) = 6.0 N m (clockwise) Torque by 15 N couple = 15 (2)(0.10) = 3.0 N m (clockwise) Net torque = 3.0 + 6.0 – 3.9 = 5.1 N m (clockwise) Q6 Ans: B Area under the graph gives the elastic potential energy of the spring. As extension is doubled from x1 to x2, area changes from ½ F1x1 to ½ F2x2. Hence change in EPE= ½ F2x2 - ½ F1x1 Q7 Ans: B ( ) ( )( ) 1 8.4 16 0.525 rad s 0.525 8.0 4.2 rad vr t     − = = = = = = Q8 Ans: D Angular speed and the linear speed are different ways of describing the same motion; they do not cause each other. By Newton’s second law, net force causes acceleration and hence changes in both angular speed and the linear speed simultaneously. M θ a Mg T

3 Tampines Meridian Junior College 2025 JC2 Preliminary Examination H2 Physics Q9 Ans: C 2 2 2 2 For an object of mass orbiting around E arth, Gravitational force provides for centripetal force 1 Since they are both orbiting around same Earth, 1 Earth Earth ISS satellit m Mm mvG rr GM v r vr v v =  =   2 4 -1 3 4.2 103.1 7.7 km s6.8 10 satellite e ISS satellite ISS satellite ISS r r rvv r  =    = = =    Q10 Ans: A The potential energy – time graph should be a sinusoidal squared graph. As the displacement at t1, t2, t3 is zero, the speed is the maximum, kinetic energy is maximum, and hence potential energy is zero. Q11 Ans: B 2 kHz has a period of 0.5 ms. A typical CRO screen has 10 horizontal divisions of 1 cm each. The period will span over 5 divisions with a 0.1 ms cm−1 setting.

Tampines Meridian Junior College 2025 JC2 Preliminary Examination H2 Physics Q12 Ans: A The two supports have to be node. Taking distance between 2 walls as L, the wavelength of the give