SAJC_Final Exam (H2) JC1 2025_timed trial

1 SAJC 2025 Final Exam Timed Trial/ 9478 [Turn Over Civic Group Index Number Name 25S ST. ANDREW’S JUNIOR COLLEGE JC 1 2025 Final Examination Time Trial PHYSICS, Higher 2 9478 19 September 2025 1 hours 20 minutes Candidates answer on the question paper. No additional materials are required. READ THESE INSTRUCTIONS FIRST Write your name, index number and Civics Group on all the work you hand in. Write in dark blue or black pen. You may use a soft pencil for any diagrams, graphs or rough working. Do not use paper clips, highlighters, glue or correction fluid. Answer all questions. The number of marks is given in brackets [ ] at the end of each question or part question. For Examiner’s Use 1 / 7 2 / 11 3 / 10 4 / 13 5 / 13 Total / 54 Percentage / 100 Grade This question paper consists of 14 printed pages including this page.

2 SAJC 2025 Final Exam Timed Trial/ 9478 [Turn Over Data speed of light in free space c = 3.00 x 108 m s-1 permeability of free space o = 4  x 10-7 H m-1 permittivity of free space o = 8.85 x 10-12 F m-1 = (1/(36)) x 10-9 F m-1 elementary charge e = 1.60 x 10-19 C the Planck constant h = 6.63 x 10-34 J s unified atomic mass constant u = 1.66 x 10-27 kg rest mass of electron me = 9.11 x 10-31 kg rest mass of proton mp = 1.67 x 10-27 kg molar gas constant R = 8.31 J K-1 mol-1 the Avogadro constant NA = 6.02 x 1023 mol-1 the Boltzmann constant k = 1.38 x 10-23 J K-1 gravitational constant G = 6.67 x 10-11 N m2 kg-2 acceleration of free fall g = 9.81 m s-2 Formulae uniformly accelerated motion s = u t + ½ a t2 v2 = u2 + 2 a s work done on/by a gas W = p V hydrostatic pressure p =  g h gravitational potential  = r Gm− displacement of particle in s.h.m. x = xo sin  t velocity of particle in s.h.m. v = v0 cos  t v =   22 0 xx −

3 SAJC 2025 Final Exam Timed Trial/ 9478 [Turn Over Answer all the questions in the spaces provided. 1 A car starts from rest and t ravels upwards along a rough straight road inclined at 5.0 o to the horizontal, as shown in Fig. 1.1 below. The length of the road is 458 m and the car has a mass of 800 kg. The speed of the car increases to 28 m s-1 at the top of the cliff. The car then veers off the cliff and lands on flat ground below. Fig. 1.1 (a) Determine the height of the top of cliff from the ground. height = ……………………. m [1] (b) Calculate the time of flight for the car to leave the cliff to the point when it lands onto the ground. time = ……………………… s [2] 5.0o cliff car 28 m s-1 u ground

4 SAJC 2025 Final Exam Timed Trial/ 9478 [Turn Over (c) When the car lands, it loses 90% of its mechanical energy after its impact with the ground. It continues to move for