TJC H2 Chem 2013 Prelim P3 Soln
Uploaded by admin · 21 February 2026
Preview
9647/03/TJC Prelim 2013 1 9647 TJC H2 Chemistry Prelim P3 Answers: 1 (a) M(NO 3)2(s) → MO(s) + 2NO2(g) + ½O2(g) Charge density of the cation decreases down the group as charge of cation is constant and ionic radius increases. Polarising power of the cation decreases resulting in less distortion of the electron cloud of the NO3 - ion, and the N-O covalent bond is weakened to a smaller extent. Therefore, ease of thermal decomposition decreases down the group. (b) (i) Mg 2+(aq) + 2OH-(aq) → Mg(OH) 2(s) A A l3+(aq) + 3OH-(aq) → A l(OH)3(s) A l(OH)3 + OH-(aq) → A l(OH)4 -(aq) B (ii) When carbon dioxide is passed into Q, the following reaction occurs. CO 2(g) + OH-(aq) → HCO 3 - (aq) The concentration of OH - decreases, causing the position of the equilibrium below to shift to the left according to Le Chatelier’s principle. Thus Al(OH)3 (white solid C) is precipitated. A l(OH)3 + OH-(aq) A l(OH)4 -(aq) Or Carbon dioxide is an acidic gas, and there will be an acid/base reaction with the Al(OH)4 - complex to form salt and water. CO 2(g) + Al(OH)4 -(aq) → HCO 3 -(aq) + Al(OH)3(s) C or 2CO2(g) + 2Al(OH)4 -(aq) → 2HCO 3 -(aq) + Al2O3(s) + 3H2O(l) C (iii) Residue A is Mg(OH)2. Mass of Mg = 24.3/58.3 x 0.18 = 0.0750 g % by mass Mg = 0.075/1.75 x 100% = 4.29 % After heating to constant mass, the residue is Al2O3(s). Mass of A l = 54/102 x 3.16 = 1.67 g % by mass A l = 1.67/1.75 x 100% = 95.4% (c) (i) (ii) 2O3 3O 2 1381
9647/03/TJC Prelim 2013 2 At t = 0 s, vol. of O3 = 38 cm3 and vol. of O2 = 762 cm3 At t = 1500 s, let vol. of O3 = (38 – y) cm3 and vol. of O2 = (3y/2 + 762) cm3 (38 – y) + (3y/2 + 762) = 818 y = 36.0 Volume of O3 = 38 – 36 = 2.00 cm3 (iii) Plot of Volume of O3 vs time. (correct labeling of axes, plotting of points) Both half-lives are constant = 400 s (indicate at least 2 t 1/2 on graph) Therefore, the reaction is first order with respect to ozone. (iv) k = ln2 / t1/2 k = 1.73 x 10-3 s-1 Rate = k[O3] 1382
9647/03/TJC Prelim 2013 3 (v) A catalyst provides alternative pathway of lower activation energy, which is the minimum amount of energy the particles must collide with for reaction to take place. The number of molecules having energy greater than or equal to activation energy increases, resulting in an increase in frequency of effective collisions and the rate of decomposition. [Total: 20] 2 (a) (i) The primary structure of a protein refers to the number and sequence of amino acids in the polypeptide chains. The amino acids are bonded by peptide bonds in the polypeptide chain. (ii) The -
Content continues in the PDF.
Related notes
- 2026 H2 Timed Practice Paper 2 Solutions + Examiner Comments (updated 17 July)MYEs/CAs/Other Tests · 2026
- 2026 H2 Timed Practice Paper 2 QP (to upload)MYEs/CAs/Other Tests · 2026
- 2026 H2 Timed Practice Paper 1 MCQ (Question Paper)MYEs/CAs/Other Tests · 2026
- 2026 H2 Timed Practice Paper 1 MCQ Combined + answer (finalised)MYEs/CAs/Other Tests · 2026
- Mock chem paper 2 suggested solutions (corrected)User Mock Papers
- NJC Organic Chem 2026Notes/Practices · 2026

