2022 RSS Phy Prelims P3 Ans
Uploaded by KeyBattleStan · 28 February 2026
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1 2022 Physics Prelim P3 – Mark Scheme Deduct 1 m if wrong dp/sf (per section) Deduct 1 m if wrong/no units (per section) Separate scoring for tabulation (sf and units). 1ai V0 = 4.50 V 1 Following results for Q1 are based on old motor ii V1 = 2.50 V I1 = 0.13 A 1 1 Old motors: 2.50 V – 2.70 V 0.12 A – 0.13 A (tested 5 pcs) New motors: 2.35 V – 2.50 V All 0.14 A (tested 6 pcs) (V1 = 1.85 V – 2.90 V) iii P1 = V1I1 = 2.50 x 0.13 = 0.33 W 1 bi V2 = 0.25 V I2 = 0.30 A 1 V2 = 0.10 V – 0.50 V I2 = 0.17 A accepted ii R = 0.25 0.30 = 0.83 Ω 1 c Q = 0.13 × 0.83 2.50 = 0.043 J 1 d While the shaft is spinning, raise the height of the boss until the shaft just stops spinning. Measure the length of the spring and find its extension, e. Remove the wooden rod and motor. Hang a known weight from the spring and find the extension of the spring. Repeat for 5 further different values of extension and known weights. Plot a graph of the extension, e against the weight. From the graph, read the value of the force that corresponds to the extension e. 1 1
2 OR Find k by hanging the 5.0 N weight on the spring. Measure the extension e. Calculate k using k = 5.0 e . Raise the boss till the motor just stops spinning. Measure the extension of the spring, e. Calculate with F = ke. 1 1 e Replace the spring with a spring balance. 1 2a h = 7.0 cm j = 32.2 cm k = 12.0 cm 1 h minimum 6.4 cm 8.5 cm NOK j = 26.8 cm NOK b t1 = 5.87 s, t2 = 5.99 s, t3 = 5.99s <t> = 5.87+5.99+5.99 3 = 5.95 s 1 1 Average of 2 timings OK c P1 = 5 × 0.010 6.0 = 0.0083 W 1 1 d t1 = 5.32 s, t2 = 5.20 s, t3 = 5.22s <t> = 5.32+5.20+5.22 3 = 5.24 s P2 = 2 × 0.010 5.24 = 0.00382 W 1 (after removing 3 weights, h = 3.7 cm) Working for <t> must be evident.
3 e Constant variables: mass-hangar and weights, change of height ∆h length k length j Independent variable: weight W Dependent variable: time taken to unwind fully, t Set up the apparatus as shown in Fig. 2.1. Carry out steps (b) and (c) to obtain a set of values of W, t and P. Repeat steps (b) and (c) to obtain 5 further sets of values of W, t and P by removing one weight from the mass-hangar for each set of reading. Tabulate the results of W, t and P. The relationship between P and W can be found by plotting a graph of P against W: 1 1 1 1 Type of weights and string used must be consistent. h, j and k must be constant as they affect the tension in the string. Dependent variable: OK if students write t and P. Graph with positive gradient (when W increases, P decreases). Accept curve graphs. P W
4 3a L0 = 0.022 m 1 bi L = 0.147 m x = 0.147-0.022 = 0.125 m x = 0.125 m 1 1 Need to show working for x. ii 1. Avoid parallax error by reading the mark on the scale of the half-metre rule at eye level when taking measurements. 2. Ensure the metre rule was vertical by aligning it to a vertical feature (eg. door frame) or the use of set square placed between the bench and the metre rule. 3. The readings of
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