2023 Sec 1 Mathematics G3 Term 1 WA1 — Question Paper & Solutions

PRESBYTERIAN HIGH SCHOOL 2023 TERM ONE WEIGHTED ASSESSMENT SECONDARY ONE MATHEMATICS G3 (4052) Name: ________________________________ ( ) Class: 1 __________ Duration: 45 minutes Date: 14 February 2023 Instructions to Candidates: Write your name, class and index number on this cover page. Answer ALL questions on the space provided. All essential workings must be shown in ink. Omission of essential working may result in loss of marks. INFORMATION FOR CANDIDATES: The number of marks is given in brackets [ ] at the end of each question or part question. You should not spend too much time on any one question. Electronic calculators are allowed in this paper. Do not open this question paper until you are told to do so. Setter: Mdm Chung Bee Chee Vetter: Mdm Herlina This paper consists of 8 printed pages (including this cover page) and 0 blank page. FOR EXAMINER’S 30 For Examiner's Use

2 Answer all the questions. 1 (a) Express 3 11 as a recurring decimal. Answer [1] (b) Choose a symbol from the list below to make a correct statement. < = > Answer 2.7 4− [1] 2 The altitudes of some places are as follows: Location Altitudes Dead Sea – 430 m Lake Assal – 153 m Mexico City 2240 m Mount Everest 8848 m Westmorland – 48 m (a) List the places that are above sea level. Answer [1] (b) Calculate the difference in altitude between Lake Assal and Dead Sea. Answer m [1]

3 [Turn over 3  , 317− , ( ) 21.4− , 2 , 1.41  (a) List all the irrational number(s). Answer [1] (b) Arrange the numbers in ascending order. Answer , , , , [2] (smallest) (largest) 4 n is a number with two decimal places. When n is rounded off to 1 decimal place, the value is 8.3. Write down the smallest and the largest possible values of n. Answer Smallest n = Largest n = [2]

4 5 Calculate 33.5 76 0.812+ . (a) Write down the first five digits of your answer. Answer [1] (b) Write your answer to part (a) correct to 3 significant figures. Answer [1] 6 When expressed as the product of its prime factors, 432160 2 3 5=   . The lowest common multiple of 144 and integer x is 2160. Find the smallest value of x. Answer x = [2]

5 [Turn over 7 (a) Find the cube of 2435 , leaving your answer in index notation. Answer [1] (b) Find the positive square root of the result in part (a). Show your workings clearly. Answer [2] (c) Find the smallest positive integer k such that 2435 k is a perfect cube. Answer k = [1]

6 8 (a) Express 108 as the product of its prime factors in index notation. Answer [2] (b) Explain why 108 is not a square number. Answer [1] (c) There are 108 oranges and 56 apples. Miss Lim wants to pack each type of fruits equally into identical boxes. Find (i) the largest number of boxes that can be packed, Answer boxes [1] (ii) the number of oranges in a box. Answer oranges [1]

7 [Turn over 9 Evaluate the following without the use of calculator. Show your workings clearly. (a) 2[( 4) ( 12)] ( 3)− + −  − Answer [2] (b) 2 1 10 13 25 8 7 21  −   Answer [3]

8 10 A water tank is 3 5 full. 4 25 of the water in the tank is used. There are now 567 litres of water left in the tank. Calculate the capacity of the tank when full. Answer litres [3] END OF PAPER

2023 Sec 1 Mathematics G3 Term 1 WA 1(a) 3 0.2711=  1(b) 2.7 > 4− 2(a) Mexico City, Mount Everest 2(b) Difference ( 153) ( 430)= − − − 153 430=− + 277= m 3(a) 2 ,  3(b) 317− , 1.41  , 2 , ( ) 21.4− ,  4 Smallest n = 8.25 Largest n = 8.34 5(a) 15.778 5(b) 15.8 6 42144 2 3= x= 33 5 135= LCM = 432 3 5 7(a) Cube of 2435 = ( ) 32435 = ( )( )( ) 2 4 2 4 2 43 5 3 5 3 5 = ( ) 6 1235 7(b) ( ) 6 1235 = ( )( ) 3 6 3 63 5 3 5 = ( ) 3635 = 421875

7(c) 2435 k = ( )( )( ) 2223 5 3 5 3 5 235k = 75k = 8(a) 23108 2 3= 8(b) Not all prime factors of 108 have power that is multiple of 2 8c(i) 23108 2 3= 356 2= 7 HCF = 22 Largest number of boxes = 4 8c(ii) No. of oranges in a box 108 4= 27= 9(a) 2[( 4) ( 12)] ( 3)− + −  − [16 12] ( 3)= −  − [4] ( 3)=  − 12=− 9(b) 2 1 3 13125 8 7 21  −   16 5 10 13 240 7 21 −=   11 10 13 240 7 21 =   11 55 28 21= 11 21 28 55= 13 45= 3 20= 10 Fraction of water not used 34 15 25 =  −