NYJC_EJC 2025 Prelim
Uploaded by sussyimpasta · 10 August 2026
Preview
©EJC NYJC 2025 9814/J2H3 Preliminary Examination/2025 [Turn over EUNOIA JUNIOR COLLEGE, NANYANG JUNIOR COLLEGE JC2 Preliminary Examination 2025 General Certificate of Education Advanced Level Higher 3 CANDIDATE NAME CIVICS GROUP 2 4 - REGISTRATION NUMBER PHYSICS Paper 1 9814/01 23 September 2025 3 hours Candidates answer on the Question Paper. No Additional Materials are required. READ THESE INSTRUCTIONS FIRST Write your name, civics group and registration number on all the work you hand in. Write in dark blue or black pen on both sides of the paper. You may use an HB pencil for any diagrams or graphs. Do not use paper clips, highlighters, glue or correction fluid. The use of an approved scientific calculator is expected where appropriate. Section A Answer all questions. You are advised to spend about 1 hour and 50 minutes on Section A. Section B Answer two questions only. You are advised to spend about 35 minutes on each question in Section B. At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. This document consists of 30 printed pages and 2 blank pages. For Examiner’s Use Section A 1 10 2 8 3 12 4 10 5 20 Section B 6 20 7 20 8 20 s.f. Total 100
2 ©EJC NYJC 2025 9814/J2H3 Preliminary Examination/2025 BLANK PAGE
3 ©EJC NYJC 2025 9814/J2H3 Preliminary Examination/2025 [Turn over Data speed of light in free space, c = 3.00 × 108 m s–1 permeability of free space, μo = 4π × 10–7 H m–1 permittivity of free space, εo = 8.85 × 10–12 F m–1 (1/(36 π)) × 10–9 F m–1 elementary charge, e = 1.60 × 10–19 C the Planck constant, h = 6.63 × 10–34 J s unified atomic mass constant, u = 1.66 × 10–27 kg rest mass of electron, me = 9.11 × 10–31 kg rest mass of proton, mp = 1.67 × 10–27 kg molar gas constant, R = 8.31 J K–1 mol–1 the Avogadro constant, NA = 6.02 × 1023 mol–1 the Boltzmann constant, k = 1.38 × 10–23 J K–1 gravitational constant, G = 6.67 × 10–11 N m2 kg–2 acceleration of free fall, g = 9.81 m s–2
4 ©EJC NYJC 2025 9814/J2H3 Preliminary Examination/2025 Formulae uniformly accelerated motion, s = ut + ½at2 v2 = u2 + 2as moment of inertia of rod through one end I = ML21 3 moment of inertia of hollow cylinder through axis I = Mr r22 12 1 ()2 + moment of inertia of solid sphere through centre I = MR22 5 moment of inertia of hollow sphere through centre I = MR22 3 work done on/by a gas, W = p ∆V hydrostatic pressure, p = ρgh gravitational potential, φ = Gm r− Kepler’s third law of planetary motion T2 = a GM π 234 temperature, T/K = T / oC + 273.15 pressure of an ideal gas, p = 21 3 Nm cV mean translational kinetic energy of an ideal gas molecule E = 3 2 kT displacement of particle in s.h.m. x = xo sin ωt velocity of particle in s.h.m. v = vo cos ωt = (
Content continues in the PDF.
Related notes
- H3 Physics - HCI 2024 Newtonian Mechanics Tutorial with SolutionsNotes/Practices · 2024
- 9814 H3 Physics - HCI 2024 Complete H3 Topical Examples and Tutorial SolutionsNotes/Practices · 2024
- 2024 RI H3 Prelim_QPExam Papers · 2024
- 2024 RI H3 Prelim_SSExam Papers · 2024
- 2019 GCE A Level 9814 H3 P1 SS [HCI]TYS Answers · 2019
- 2020 GCE A Level 9814 H3 P1 SS [HCI]TYS Answers · 2020

