RVHS 2025 Prelim
Uploaded by sussyimpasta · 22 August 2026
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RIVER VALLEY HIGH SCHOOL JC 2 PRELIMINARY EXAMINATIONS H3 PHYSICS 9814 24 S EPTEMBER 2025 3 H OURS CANDIDATE NAME CENTRE NUMBER S INDEX NUMBER CLASS 2 4 J INSTRUCTIONS TO CANDIDATES DO NOT OPEN THIS BOOKLET UNTIL YOU ARE TOLD TO DO SO. Read these notes carefully. Write your name, class and index number above . Write in dark blue or black pen on both sides of the paper. You may use an HB pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. The use of an approved scientific calculator is expected where appropriate. Section A Answer all questions You are advised to spend about 1 hour 50 min on Section A. Section B Answer all questions You are advised to spend about 1 hour 10 min on Section B. At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. FOR EXAMINERS’ USE Section A 1 /7 2 /15 3 /8 4 /15 5 /15 Section B 6 /20 7 /20 Deduction TOTAL /100 River Valley High School Page 1 of 29 H3 Physics 9814 JC 2 Preliminary Examinations 2025
________________________________________________________________________ This Question Paper consists of 29 printed pages. River Valley High School Page 2 of 29 H3 Physics 9814 JC 2 Preliminary Examinations 2025
Data speed of light in free space c = 3.00 × 10 8 m s –1 permeability of free space μ 0 = 4 × 10 –7 H m –1 permittivity of free space ε 0 = 8.85 × 10 –12 F m –1 (1/(36 )) × 10 –9 F m –1 elementary charge e = 1.60 × 10 –19 C the Planck constant h = 6.63 × 10 –34 J s unified atomic mass constant u = 1.66 × 10 –27 kg rest mass of electron m e = 9.11 × 10 –31 kg rest mass of proton m p = 1.67 × 10 –27 kg molar gas constant R = 8.31 J K –1 mol –1 the Avogadro constant N A = 6.02 × 10 23 mol –1 the Boltzmann constant k = 1.38 × 10 –23 J K –1 gravitational constant G = 6.67 × 10 –11 N m 2 kg –2 acceleration of free fall g = 9.81 m s –2 Formulae uniformly accelerated motion moment of inertia of rod through one end Ι = 1 3 𝑀 𝐿 2 moment of inertia of hollow cylinder through axis 𝐼 = 1 2 𝑀 ( 𝑟 1 2 + 𝑟 2 2 )moment of inertia of solid sphere through centre Ι = 2 5 𝑀 𝑅 2 moment of inertia of hollow sphere through centre Ι = 2 3 𝑀 𝑅 2 work done on/by a gas hydrostatic pressure gravitational potential Kepler’s third law of planetary motion 𝑇 2 = 4 π 2 𝑎 3 𝐺𝑀 temperature T / K = T / ° C + 273.15 pressure of
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