NYGH 2018-S3EOY-IM2 Ans

IM2 SECONDARY 3 EOY 2018 ANSWERS Number Answers 1(i) A = 875 1(ii) The disease has not infected 95 people at the end of Day 7. 2(i) sinθ=1k 2(ii) sec2θ=k2k2−1 2(iii) tanθ=−1k2−1 3(b) θ=10.3°,119.7°,190.3°,299.7° 4 p=1, q=13 5(i) Amplitude=2 Period=2π. 5(ii) 6(i) 7 6(ii) (1, 0) 6(iii) x = 1 6(iv) −5,1012⎛⎝⎜⎞⎠⎟ 7(a) x=−43 or x=−1 7(b) y = 4.74 7(c) w=13 . x y 0 0.5π π 1.5π 2π 2.5π 3π0 1 2

8(a) y=2x−112⎛⎝⎜⎞⎠⎟2−712 Minimum value of h is −712. 8(b) b < –4 or b > 4 8(c) 8𝑥!−232𝑥−343=0. 9(a) x>0, x≠1 9(b) Add the line y = 5 – 4x Number of solution = 2 10(i) The other linear factor is 2x – 3. 10(ii) f(x)+8f(x)=1+12(2x−3)−12(2x+1)−2(2x + 1)2 11(i) h2−212⎛⎝⎜⎞⎠⎟=1 11(ii) 11(iii) h– 1: x !x−42, x<0,x−2, x≥0.⎧⎨⎪⎩⎪ 12 Bonus α−β=33−6. x y -14-12-10-8-6-4-202468101214 -4 -2 0 2 4 6 8 2 4 0 x y