Topical Revision Paper 1 Unit 1 Advanced Algebraic Manipulations
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Text from the first pagesTopical Revision Paper 1 Term 1 Unit 1 Advanced Algebraic Manipulation Question 1: Given that 22 44x x y y and that xy , find the value of 3 xy . [3] Solution: 22 4 4 ( )( ) 4( )x x y y x y x y x y Since xy , 04x y x y Hence 3 3 4xy 6 Question 2: Simplify into a single fraction 3 3 2 3 2 2 2 8 16 4 4 (4 2 ) x y xy x x y y x . [4] Solution: 3 3 2 3 2 2 2 22 2 8 16 4 4 (4 2 ) ( 2 )( 2 4 ) 4 (2 )(2 ) ( 2 )( 2 ) 4(2 ) x y xy x x y y x x y x xy y x y x y x x y x y yx 2 2 22 4 2 22 x xy y xy x x y y x 2224 2 xy xy Question 3: (a) Factorise completely 3 2 2 32 6 8 24a a b ab b . [3] (b) Make q the subject of the formula 2249pq q p . [3] Solution: a) 3 2 2 32 6 8 24a a b ab b
222 ( 3 ) 8 ( 3 )a a b b a b 22(2 8 )( 3 )a b a b 2( 2 )( 2 )( 3 )a b a b a b (b) 2249pq q p 2 2 2 2 49p q q p 2 2 2(4 ) 9q p p 2 2 2 93 or 4 4 ppq p p Question 4: (a) It is given that 2 2 1 1 R v c . (i) Find the value of R when 5v and 3c . [1] (ii) Express v in terms of R and c . [3] (b) Factorise completely 4 2 2 14 49x x xy y . [3] Solution: (a) 1 51 9 1= 2 3 3= 2 R
(b) 2 2 2 2 22 2 22 2 2 2 2 2 2 22 2 1 1 or or 1 R v c c cv ccv R c R c cv c v RR cvR R (c) 4 2 2 4 2 2 24 22 14 49 14 49 7 7 7 x x xy y x x xy y x x y x x y x x y Question 5: (a) Given that 4 3 2a b a b , find the value of 22 2 2 ab ab . [3] (b) Solve for x and y if 333 1 2 5 3 0x y x y . [4] Solution: (a) 222 2 4 3 2 35 3 a 5 322 30 5 2 43 32 5 a b a b ab b aaab ab aa (b)
3 3 3 3 3 1 2 6 2 (1) 2 5 3 (2) (1) (2) : 1 1 sub into (1) 31 4 16 xy xy xy y y x x x
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