PLMGS 2026 Physics P2 QP

[Turn over CENTRE NUMBER S INDEX NUMBER Physics (G3) 6091/02 Paper 2 25 August 2026 1 hour 45 minutes Candidates answer on the Question Paper. No Additional Materials are required. READ THESE INSTRUCTIONS FIRST Write your name and index number on all the work you hand in. Write in dark blue or black pen. You may use a soft pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. Section A Answer all questions. Write your answers in the spaces provided. Section B Answer one question. Write your answers in the spaces provided. Indicate the question number in the grid provided. Candidates are reminded that all quantitative answers should include appropriate units. The use of an approved scientific calculator is expected, where appropriate. Candidates are advised to show their working in a clear and orderly manner, as more marks are awarded for the sound use of Physics than for correct answers. At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. This document consists of 24 printed pages. CANDIDATE NAME ( ) CLASS TG Paya Lebar Methodist Girls’ School (Secondary) Preliminary Examination 2026 Secondary 4 Express Secondary 4 Express / G3 For Examiner’s Use Section A / 70 Section B Qn _____ / 10 Total / 80

2 Section A Answer all questions. This section is worth 70 marks. 1 Ball A is projected upwards under the influence of Earth’s gravity. There is no air resistance acting on it. Fig. 1.1 shows the velocity-time graph of this ball. Fig. 1.1 (a) Given that the magnitude of acceleration due to Earth’s gravity is 10 m/s2, calculate t1. t1 =………………… [1] (b) Hence, calculate the maximum height reached by ball A. maximum height = ……………. [2] (c) Ball B is projected upwards with the same initial velocity as ball A. However, air resistance acts on ball B. The mass of ball B is the same as ball A. (i) On Fig. 1.1, sketch a graph to show the motion of ball B from the start until it reaches maximum height. Label your graph as B. [2] v / ms-1 t / s 25 t1 ball A 0

3 [Turn over (ii) Using idea of forces and resultant force, explain the shape of your graph in (c)(i) and describe its motion. …………………………………………………………………………………… …………………………………………………………………………………… …………………………………………………………………………………… [2] [total: 7 marks] 2 Fig. 2.1 shows a man in three different stages of a bungee jump. The chord attached to the man is elastic in nature. There is no air resistance acting on the man. Fig. 2.1 The man falls from rest at position O at the jump platform. The chord starts to stretch at position A. The greater the stretching of chord, the larger its tension. The man reaches maximum speed at position B and after B, the man starts to decelerate. At position C, the man comes to a rest momentarily. (a) (i) Label the force(s) acting on the man before he reaches position A. Name the force(s). [1] (ii) Label the force(s) acting on the man when he is in between position A and B. Name the force(s). [1] at position C in between A and B before reaching A O O O A A A B B B C C C

4 (iii) On Fig. 2.2, sketch the speed-time graph of the man from position O to position B. [2] Fig. 2.2 (b) The gravitational field strength is g = 10 N/kg. (i) With reference to Fig. 2.1 and ideas of resultant force, explain why the man decelerates from B to C. …………………………………………………………………………………. …………………………………………………………………………………. [1] (ii) The man has a mass of 60kg. At position C, his deceleration is 3.0 m/s2. Calculate the upward force due to chord acting on him at this instant. tension = ……………….. [2] [total: 7 marks] v / ms-1 t / s 0 position A position B

5 [Turn over 3 (a) State what is meant by the centre of gravity of an object. ………………………………………………………………………………………… [1] (b) A non-uniform rod XY is pivoted at point P, as shown in Fig. 3.1. Fig. 3.1 (not to scale) The rod has length 4.00 m and weight 44.0 N. The centre of gravity of the rod is 1.70 m from end X of the rod. Point P is 1.10 m from end X. A sphere hangs by a wire from end Y of the rod. The weight of the sphere is 3.0 N. The weight of the wire is negligible. A force F is applied vertically downwards at end X so that the horizontal rod is in equilibrium. (i) Calculate the mass of the sphere. mass = ……………. [1] (ii) By taking moments about P, calculate F. F = ………………. F [2] (iii) Calculate the force exerted on the rod by the pivot. force = ……………… [2] [total: 6 marks] F X P Y 3.0 N 44.0 N 4.00 m 1.70 m 1.10 m wire sphere

6 4 A child of weight 330 N is at point X at the top of a slide. The slide is at the edge of a swimming pool, as shown in Fig. 4.1. Fig. 4.1 The child moves from rest to the lowest point of the slide that is a vertical distance of 4.0 m below X. The child continues moving towards point Y which is at the end of the slide and a vertical distance of 1.1 m above the lowest point. The energy in the kinetic store of the child at Y is 540 J. (a) Calculate the difference in the energy in the gravitational potential store of the child at points X and Y. difference in energy = ………………….J [2] (b) An average frictional force of 52 N acts on the child when moving from X to Y. By considering energy transfer, determine the distance moved by the child from X to Y. distance moved = ………………m [2] (c) With the concept of energy stores, describe how energy in the gravitational potential store is transferred as the child moves from X to Y. …………………………………………………………………………………………. ………………………………………………………………………………………….. [2]

7 [Turn over (d) Calculate the speed of the child at point Y. speed = ……………m/s [2] [total: 8 marks] 5 Fig. 5.1 shows a U-tube glass with uniform cross sectional area of 0.80 cm2 It is used to determine the density of oil. The density of mercury and water are 13600 kg/m3 and 1000 kg/m3 respectively. The atmospheric pressure is taken to be 101000 Pa. Fig. 5.1 (a) By considering the relationship between the weight of oil and water, calculate the density of the oil. density of oil = ……………….kg/m3 [2] (b) Calculate the pressure at B. pressure = ……………..Pa [2]

8 (c) Fig. 5.2 shows another tube, identical to the U-tube except for a cone-shaped opening on the left, is filled with the same volume of mercury as in the previous set-up. Fig. 5.2 Oil and water are poured respectively into the left and right sides of the tube. The volume of water that is poured into this set-up is exactly the same as the previous one. State and explain i