TJC_H1_PHY_P2_Solutions
Uploaded by hima · 3 June 2023
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Solution to 2016 H1P2 1 (a) Rate of change of velocity A1 (b)(i) x = 72 t A1 (b)(ii) y =½ (9.81) t 2 = 4.91 t 2 A1 (c) 100 = 4.91 t 2 t = 4.5 s M1 A1 (d) v = [(72 x 4.5) – 125] / [4.5] v= 44.2 m s -1 (160 km h -1 ) M1 A1 2 (a) Product of force and perpendicular distance of the line of force from fixed point/axis B1 (b)(i) Label normal contact force N 1 at wall; normal contact force N 2 at the ground and friction at the ground correctly Label weight of man and weight of ladder correctly B1 B1 (b)(ii) As system is in equilibrium, N2 = (72 + 40) x 9.81 = 1100 N M1 A1 (b)(iii) cos = 6.0/12.0 = 60 (or other methods) Let L be the length of ladder, Taking moments about D, N1sin60 x L = (72 x 9.81 x cos 60) (3L/4) + (40 x 9.81 cos 60) (L/2) N1 = 419 N M1 A1 3 (a) Electrical resistance of a conductor is defined as the ratio of the potential difference across it to the current flowing through it. B1 (b)(i) When S1 is the only switch closed, lamps A and C are in series giving a resistance of 30.0 Ω. Thus, resistance of a lamp is 15 Ω. Or when all three switches are closed, lamps A and C are in parallel with lamps B and D giving a resistance of 15 Ω. Thus, resistance of a lamp is 15 Ω. B1 (ii) faulty lamp: lamp E nature of fault: lamp is short-circuited B1 B1 (iii) Short-circuited lamp could cause excessive current to flow in the circuit that could cause damage to the power supply / other lamps / blow fuse in power supply. B1 (c)(vi) Using V = I R R = V / I = 12.0 / 0.40 = 30.0 B1 (c)(v) The lamp filament in (v)1 has a higher resistance than (iii) because it is hotter when operating at normal brightness. B1
2 4(a) Magnetic flux density is defined as the force per unit length acting on a straight conductor with unit current placed perpendicular to the magnetic field. B2 4(b)(i) B1 – Correct direction B1 – Three concentric circles with increasing spacing 4(b)(ii) B1 – Uniform field near poles of magnetic B1 – Stronger field on top, weaker field below 4(b)(iii) Towards the bottom of the page. B1 4(b)(iv) Magnetic force = (0.50)(1.5)(0.10) = 0.075 N B1
3 5 (a)(i) resistance of LDR = 0.20 kΩ B1 (ii) (A logarithmic scale compresses the scale so that the widely differing values can be shown easily on one graph. B1 (iii) On the logarithmic scale in Fig. 7.1, the graph is similar to lg R against lg I. It is a straight line with gr adient = -1 and y -intercept = lg 10000, the relation is true. B2 (b)
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