Additional_Mathematics_Notes
Uploaded by hima Β· 12 June 2023
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Additional Mathematics Notes Functions and Graphs 2π₯#+2 π>0 Turning point = Minimum point β2π₯#+2 π<0 Turning point = Maximum point Line of symmetry always passes through the turning point (π₯-coordinate of turning point/mid-value of π₯-intercepts) y-intercept, x=0 π¦=ππ₯#+ππ₯+π π¦=π(0)#+π(0)+π x-intercept, y=0 0=ππ₯#βππ₯+π Completing the Square ππ₯#+ππ₯+π π(π₯#+πππ₯+ππ) π0(π₯+π2π)#β1π2π2#+ππ3 π(π₯+β)#+π π(π₯ββ)#+π Coefficient of π₯# must be +1 ππ₯#βππ₯+π π(π₯#βπππ₯+ππ) π0(π₯βπ2π)#β1π2π2#+ππ3 Conditions for Curve to Lie Completely Above or Below x-axis Above Coefficient of π₯#>0 Minimum value is positive π#β4ππ<0 β΄Since the coefficient of π₯#=1>0 and the minimum value of π¦=4, which is positive, the curve lies completely above the x-axis. Below Coefficient of π₯#<0 Minimum value is negative β΄Since the coefficient of π₯#=β1<0 and the maximum value of π¦=β4, which is negative, the curve lies completely below the x-axis. Quadratic Formula (Given) ππ₯#+ππ₯+π π₯=βπΒ±βπ#β4ππ2π Nature of Roots of Quadratic Equations π#β4ππβ₯0 Real roots π#β4ππ>0 2 real and distinct roots π#β4ππ<0 Non-real roots π#β4ππ=0 2 real and equal roots Intersection Between Line and Curve π#β4ππ>0 Line cuts curve at 2 distinct points π#β4ππ=0 Line cuts curve at 1 point (Line is tangent to curve) π#β4ππ<0 Line does not intersect curve Finding Range of Values E.g. (πβ6)(π+2)>0 Draw number line and curve Laws of Surds βππ βπΓβπ ?ππ βπβπ βπΓβπ, (βπ)# π πβπ+πβπ (π+π)βπ πβπβπβπ (πβπ)βπ π#+(πβπ)# π#+π#π 1β2+3 1β2+3Γβ2β3β2β3 β2β32β9 ββ2β37 Equality of Surds π+πβπ 5+4βπ π=5 π=4
Polynomials Degree of π(π₯)Γπ(π₯) Degree of π(π₯) + Degree of π(π₯) Division Algorithm: π(π₯)=π·(π₯)Γπ(π₯)+π (π₯) π(π₯) = Dividend π·(π₯) = Divisor π(π₯) = Quotient π (π₯) = Remainder Remainder and Factor Theorem π(π₯)Γ·(ππ₯+π) π ππππππππ=π(βππ) Factor Theorem, Remainder=0 Cubic Expressions and Equations ππ₯R+ππ₯#+ππ₯+π (ππ₯+π)(βπ₯+π)(ππ₯+π) (ππ₯+π)(ππ₯#+ππ₯+π) Step 1 Factorise π(π₯) using Factor Theorem [Mode-3-4] Step 2 Use Synthetic Division/ Long Division/ Comparing Coefficients to factorise π(π₯) completely Synthetic Division π(π₯)=2π₯Rβ11π₯#β7π₯+6 -1 2 -11 -7 6 -2 13 -6 2 -13 6 0 (π₯+1) π(π₯)=(π₯+1)(2π₯#β13π₯+6) Cubic Identities Sum of cubes πR+πR=(π+π)(π#βππ+π#) Difference of cubes πRβπR=(πβπ)(π#+ππ+π#) Partial Fractions Step 1: Fraction must be a proper fraction (Degree of numerator < Degree of denominator) Step 2: Factorise denominator Step 3: Express proper algebraic fraction in partial fractions Case Denominator Proper Fraction Partial Fraction 1 Distinct linear factors ππ₯+π(ππ₯+π)(ππ₯+π) π΄ππ₯+π+π΅ππ₯+π 2 Repeated linear factors ππ₯+π(ππ₯+π)# π΄ππ₯+π+π΅(ππ₯+π)# 3 Quadratic factor (cannot be factorised) ππ₯#+ππ₯+π(ππ₯+π)(π₯#+π#) π΄ππ₯+π+π΅π₯+πΆπ₯#+π# Step 4: Solve for unknown constant Binomial Theorem (Given) Binomial expansion of (π+π)V Wπ0XπV+Wπ1XπVYZπ+Wπ2XπVY#π#+β―+WππXπVY\π\+Wππβ1XππVYZ+(ππ)πV General Term π\^Z=WππXπVY\π\ Law of Indices π_=1 π`ΓπV=π`^V πYV=1πV π`Γ·πV=π`YV π`V=βπ`a (π`)V=π`V (ππ)V=πVπV (ππ)V=πVΓπ
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