HCI 2022 Prelim P2
Uploaded by jelly · 8 September 2023
Preview
This document consists of 25 printed pages. HWA CHONG INSTITUTION JC2 Preliminary Examination Higher 2 CANDIDATE NAME CT GROUP 21S CENTRE NUMBER INDEX NUMBER PHYSICS Paper 2 Structured Questions Candidates answer on the Question Paper. No Additional Materials are required. 9749/02 13 September 2022 2 hours READ THESE INSTRUCTIONS FIRST Write your Centre Number, index number and name in the spaces at the top of this page. Write in dark blue or black pen on both sides of the paper. You may use a soft pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. The use of an approved scientific calculator is expected, where appropriate. The number of marks is given in brackets [ ] at the end of each question or part question. You are reminded of the need for good English and clear presentation in your answers. For Examiner’s Use Paper 2 1 11 2 8 3 10 4 8 5 10 6 11 7 22 Deductions Total 80
2 © Hwa Chong Institution 2022 9749 / JC2 Preliminary Examination Data Formulae speed of light in free space, c = 3.00 10 8 m s -1 permeability of free space, o = 4 10 -7 H m -1 permittivity of free space, o = 8.85 10 -12 F m -1 (1/(36)) 10 -9 F m -1 elementary charge, e = 1.60 10 -19 C the Planck constant, h = 6.63 10 - 34 J s unified atomic mass constant, u = 1.66 10 -27 kg rest mass of electron, me = 9.11 10 -31 kg rest mass of proton, mp = 1.67 10 -27 kg molar gas constant, R = 8.31 J K -1 mol -1 the Avogadro constant, NA = 6.02 10 23 mol -1 the Boltzmann constant, k = 1.38 10 -23 J K -1 gravitational constant, G = 6.67 10 -11 N m 2 kg -2 acceleration of free fall, g = 9.81 m s -2 uniformly accelerated motion work done on / by a gas hydrostatic pressure gravitational potential temperature pressure of an ideal gas mean kinetic energy of a molecule of an ideal gas displacement of particle in s.h.m. velocity of particle in s.h.m. electric current resistors in series resistors in parallel electric potential alternating current / voltage magnetic flux density due to a long straight wire magnetic flux density due to a flat circular coil magnetic flux density due to a long solenoid radioactive decay decay constant s = ut + 2 1 at2 v 2 = u 2 + 2as W = p V p = gh r Gm−= T/K = T/ C + 273.15 P = 21 3 Nm cV kTE 2 3= x = xo sin t v = vo cos t = )( 22 xxo − I = Anvq R = R1 + R2 + . . . 1/R = 1/R1 + 1/R2 + . . . r QV o4= x = xo sin t 2 oμB d= I 2 oμNB r= I B = onI x = xo exp ( -
Content continues in the PDF.
Related notes
- YIJC Topic 4_MCQ_Set A and BNotes/Practices · 2026
- 16. Capacitors (2026) notes NJCNotes/Practices · 2026
- 16PS. Capacitors (2026) tutorial solutions NJCNotes/Practices · 2026
- 16P. Capacitors (2026) NJC tutorial Notes/Practices · 2026
- 16ES. Capacitors (2026) notes NJC exercise solutions Notes/Practices · 2026
- NJC H2 Physics Term 1 Timed Practice P2 with solutionMYEs/CAs/Other Tests · 2026

