2014 H2 Physics MS EJC Suggested

©EJC 2020 9646/H2 PHYSICS 2014 EUNOIA JUNIOR COLLEGE General Certificate of Education Advanced Level Higher 2 PHYSICS SUGGESTED SOLUTIONS 9646 October/November 2014 Paper 1 Multiple Choice Question Key Question Key 1 C 21 D 2 A 22 C 3 A 23 B 4 D 24 D 5 D 25 A 6 C 26 D 7 C 27 D 8 D 28 B 9 C 29 A 10 D 30 D 11 B 31 D 12 B 32 C 13 B 33 D 14 C 34 B 15 A 35 D 16 B 36 C 17 A 37 A 18 C 38 D 19 A 39 A 20 D 40 C Notes Q4: need to solve simultaneous equations, one equation with unknown time and 0.25 of distance, d, from start to ground, the other equation with required time and d Q9: calculate power output of the train first Q22: distance between 2 nodes, i.e. 2 minimum points on voltage graph is half a wavelength, not one wavelength Q25: directions of field at all 4 points are the same even though their magnitude is different Q28: current is given by charge x frequency, ef = eω/2π

©EJC 2020 9646/H2 PHYSICS 2014 Paper 2 Structured Questions Qns Marks 1(a)(i) magnitude = 60.0 N angle = 90° B1 B1 1(a)(ii) vector sum of forces = 0 along horizontal considering magnitudes: ( ) ( ) ( ) 22 cos 200 cos 30 sin 200 sin 30 sin 40 0 40 0 sin 40 cos 100 horizontally: 100 3 N vertically: 60 0 N / (20 79)) magnitude of 40 100 3 20 79 178 N tan 3 13 or 347 Y Y Y. x arcsin( . Y Y . Y θ θ θ θ θ θθ = +  = °= °= = + = = = − = − −= = −° ° Notes Do not miss out the negative signs in your working and answer. M1 A1 A1 Y S 60.0 N θ Y S 60.0 N

3 ©EJC 2020 9646/H2 PHYSICS 2014 [Turn over Qns Marks 1(b) [magnitude] as long as magnitude of X is above zero [direction] and X remains directed at 30° anticlockwise to the horizontal, there will be a horizontal component of force cosX θ acting on S to the right since vector sum of forces on S must be zero for S to be in equilibrium, Y must provide a horizontal component force acting on S to the left Y is along same direction as rope B, so must be at an angle to the left and cannot be parallel to weight of S Notes Cannot just describe general conditions for equilibrium rather than target it towards the context of this question, i.e. must focus on forces acting on object S. B1 B1 A0 2 (out of syllabus) 3(a) current decreases as resistance of R and total circuit resistance increases drop in p.d. across internal resistance decreases ( )int resistanceV r= I terminal p.d. increases as it is the difference between electromotive force and p.d. drop across internal resistance ( )terminal e.m.f. rV = − I Notes Remember that the terminal potential difference is not the potential difference across the internal resistance. Also do not simply quote the potential divider formula without explaining in detail. M1 M1 A1

4 ©EJC 2020 9646/H2 PHYSICS 2014 Qns Marks