EJC Physics 2024 J2 H1 MYE QP

©EJC 2024 8867/J2H1MYE2024 [Turn over EUNOIA JUNIOR COLLEGE JC2 MID YEAR EXAMINATIONS 2024 General Certificate of Education Advanced Level Higher 1 CANDIDATE NAME CIVICS GROUP 2 3 - REGISTRATION NUMBER PHYSICS Structured Questions 8867/02 June 2024 2 hours READ THESE INSTRUCTIONS FIRST Write your name, civics group and registration number on all the work you hand in. The use of an approved scientific calculator is expected where appropriate. Write in dark blue or black pen on both sides of the paper. You may use an HB pencil for any diagrams or graphs. Do not use paper clips, highlighters, glue or correction fluid. Section A Answer all questions from this section. Section B Answer one question from this section. The number of marks is given in brackets [ ] at the end of each question or part question. This document consists of 24 printed pages and 0 blank page. For Examiner’s Use Q1 9 Q2 7 Q3 8 Q4 8 Q5 10 Q6 8 Q7 10 Q8 20 Q9 20 Total 80

2 ©EJC 2024 8867/J2H1MYE2024 Data Formulae uniformly accelerated motion = + ++ = + = + + =   2 22 12 12 1 2 2 11 1 s at u as R /R /R u v /R t RR resistors in series resistors in parallel speed of light in free space − − − − − − −− − × × = × × × = × = = = × = = = 81 19 27 31 e 27 p 23 1 A 11 2 2 2 3 00 1 60 9 11 1 10 m s 10 C 1 66 10 kg 10 kg 10 kg 6 02 10 mol 10 N m k 6 1 g m 7 s 7 66 98 c u . e. . . N G. g . m m . . elementary charge unified atomic mass constant rest mass of electron rest mass of proton the Avogadro constant gravitational constant acceleration of free fall

3 ©EJC 2024 8867/J2H1MYE2024 [Turn over Section A Answer all the questions in this section in the spaces provided. 1 (a) The volume of a cone, V, can be calculated using the formula 21 3π=V rh where r is the radius of its base and h is its height. In an experiment, a metal cone is measured with a mass m of (0.170 ± 0.001) kg and a height of (12.0 ± 0.1) cm. It has a circular base with diameter d of (5.00 ± 0.02) cm. Determine the density of the cone with its actual uncertainty. density of cone = (………………… ± ………….) kg m −3 [4]

4 ©EJC 2024 8867/J2H1MYE2024 (b) Two masses A and B are allowed to slide down a frictionless slope as shown in Fig. 1.1 below. Fig 1.1 Explain if there would be normal contact force between the surface of block A and B. ............................................................................................................................................... ...........................................................................................................................................[1] (c) The two masses are now pushed along a horizontal frictionless surface by a 350 N force as shown in the Fig.1.2. Mass A is 10 kg and mass B is 11 kg. Fig 1.2 (i) Calculate the acceleration of the masses. acceleration = ................................... m s−2 [2] (ii) Determine the magnitude of the normal contact force by mass B on mass A. force = …................................ N [2] [9 marks] A B 350 N A B

5 ©EJC 2024 8867/J2H1MYE2024 [Turn over 2 (a) Explain what is meant by acceleration. ……….................................................................................................................................... ...........................................................................................................................................[1] (b) The velocity-time graph in Fig . 2.1 shows the first 2.5 s of the motion of a ball which is thrown vertically downward at an initial speed of 6.0 m s −1. The effect of air resistance is negligible. Fig 2.1 (i) Calculate the distance the ball travelled before hitting the ground. distance = ................................... m [2] (ii) Suggest why rebound speed of the ball is different from speed upon impact with the ground. ................................................................................................................................... ...............................................................................................................................[2] velocity / m s−1 time / s 0.5 1.0 1.5 2.0 2.5 0 10 20 −20 −10 A B C D 0.

6 ©EJC 2024 8867/J2H1MYE2024 (iii) Suggest why gradient of the lines AB and CD are the same. .................................................................................................................................. ...............................................................................................................................[2] [7 marks]

7 ©EJC 2024 8867/J2H1MYE2024 [Turn over 3 A window panel is hinged at its top end, and supported by a rod close to its lower side, as shown in Fig. 3.1. Fig. 3.1 (not to scale) The window panel weighs 250 N and is opened to an angle 30° to the vertical. The glass used for the window panel is not uniform and the centre of gravity of the window panel is not at its geometrical centre. The rod exerts a force of 90 N perpendicular to the window panel, at a distance of 120 cm from the top. (a) State two conditions required for the window panel to be in a state of equilibrium. 1. ..................................................................................................................................... 2. .................................................................................................................................[2] (b) State what is meant by centre of gravity of the window panel. ........................................................................................................................................... .........................................................................................................................................[1] window panel wall 90 N hinge 30° 250 N rod centre of gravity

8 ©EJC 2024 8867/J2H1MYE2024 (c) Use the principle of moments to determine the distance between the centre of gravity of the window panel and the smooth hinge. distance = ................................... m [2] (d) On Fig. 3.1, draw an arrow to indicate the direction of the force on the window panel at the hinge and label it H. [1] (e) Determine the magnitude of the force acting on the window panel at the hinge. force = ................................... N [2] [8 marks]

9 ©EJC 2024 8867/J2H1MYE2024 [Turn over 4 Fig. 4.1 shows a 1.5 kg cart A with a force sensor in the front that is moving with a velocity of 3.0 m s−1 until it collides with a stationary cart B of an unknown mass m. Fig. 4.1 After the collision, cart B moves off with a velocity of 2.4 m s−1. Friction is negligible in the entire process. The datalogger connected to the force sensor generated a force -time graph for the impact as shown in Fig. 4.2, showing the magnitude of force experienced by cart A. Fig. 4.2 (a) State Newton’s Second Law of Motion. …….................................................................................................................................... ……................................................................................................................................... ……................................................................................................................................[1] B m A 1.5 kg 3.0 m s−1 force sensor 0 time t / ms force F / kN 0