EJC Physics 2022 J2 H1 MYE P2 MS

1 ©EJC 2022 8867/J2H1MYE/2022 EUNOIA JUNIOR COLLEGE JC2 MID-YEAR EXAMINATIONS 2022 General Certificate of Education Advanced Level Higher 1 H1 PHYSICS PAPER 2 MARK SCHEME 8867 Jul 2022 1 (a) X IV X IV ∆ ∆∆= + 0.1 0.03 4.9 3.00= + = 0.030 100%X X ∆ × = 3.0% M1 A1 (b) 3 3.00 4.9 10 VX I −= = × = 612 Ω X = 0.030 x 612 = 20 Ω (to 1 s.f.) X ± X = (610 ± 20) Ω M1 M1 A1 2 (a) Rate of change of velocity with respect to time. B1 (b)(i) Vertical acceleration = - 2.5 / 0.625 = - 4.0 m s-2 (accept from -3.9 to -4.1 m s-2 ) M1 A1 (ii) Taking upward as positive, v2 = u2 + 2as v2 = (5.0 sin 30o)2 + 2(- 4.0)(-1.1) v = -3.9 ms-1 M1 A1 (iii) Taking upward as positive, v = u + at -3.9 = 5.0 sin 30o + (- 4.0) t t = 1.6 s OR: Explain their method of determining by reading off from the graph the time for which v = - 3.9 ms-1 M1 A1 (iv) Area bounded by the line between 1.25 s and 1.60 s. (can accept ±half small square for each timing above) B1

2 ©EJC 2022 8867/J2H1MYE/2022 (v) ‘X’ marked at velocity of - 4.3 m s-1. When the velocity is 45 o with respect to the vertical, both vertical and horizontal velocity are of the same magnitude, i.e. vx = 5.0 cos 30o = 4.3 m s-1. B1 B1 3 (a) Total momentum of the system remains constant, provided no external resultant force acts on the system. B1 B1 (b)(i) 1. v = u +at v = 100 + (– 900)(0.030) = 73 m s-1 A1 2. v = u +at v = 0 + 300(0.030) = 9.0 m s-1 A1 (b)(ii) Impulse = change in momentum = (0.010)(73 – 100) = – 0.27 Ns or kg ms-1 (with correct magnitude & units) OR Impulse = F ∆t = (ma) ∆t = (0.010 x 900)(0.030) = 0.27 Ns (with units) M1 A1 (iii) Mbulletubullet + mblockublock = mbulletvbullet + mblockvblock (0.010)(100) + mblock (0) = (0.010)(73) + mblock(9.0) mblock = 0.030 kg M1 A1 (iv) Total Initial Kinetic energy = (1/2)(0.010)(100)2 = 50 J Total Final Kinetic energy of bullet and block = (1/2)(0.010)(73)2 + (1/2)(0.030)(9.0)2 = 28 J Collision was inelastic as total kinetic energy is not conserved. OR: relative speed of approach = 100 – 0 = 100 m s -1 relative speed of separation = 9.0 – 73 = – 64 m s-1 Collision was inelastic since relative speed of separation is NOT equal to relative speed of approach. M1 A1 4(a)(i) No resultant force acting in any direction. No resultant moment about any point. B1 B1

3 ©EJC 2022 8867/J2H1MYE/2022 (ii) 1. Clockwise moment about base = 180