2024 CJC H1.Phy.PRELIM_P2_ans

CANDIDATE NAME CLASS 2T PHYSICS 8867/2 Paper 2 Structured Questions 23 August 2024 2 hours Candidates answer on the Question Paper. No additional materials are required. READ THESE INSTRUCTIONS FIRST Write your name and class on all the work you hand in. Write in dark blue or black pen on both sides of the paper. You may use an HB pencil for any diagrams or graphs. Do not use staples, paper clips, glue or correction fluid. The use of an approved scientific calculator is expected, where appropriate. Section A Answer all questions. Section B Answer any one question. At the end of the examination, fasten all your work securely together. The number of marks is given in brackets [ ] at the end of each question or part question. MARK SCHEME This document consists of 27 printed pages and 1 blank page. [Turn over FOR EXAMINER’S USE DIFFICULTY L1 L2 L3 Q1 / 7 Q2 / 7 Q3 / 7 Q4 / 8 Q5 / 8 Q6 / 7 Q7 / 16 Q8 / 20 Q9 / 20 PAPER 2 (WEIGHTAGE: 67%) / 80 PAPER 1 (WEIGHTAGE: 33%) / 30 TOTAL % Catholic Junior College JC2 Preliminary Examination Higher 1

2 Data speed of light in free space, c = 3.00  108 m s1 elementary charge, e = 1.60  1019 C unified atomic mass constant, u = 1.66  1027 kg rest mass of electron, me = 9.11  1031 kg rest mass of proton, mp = 1.67  1027 kg the Avogadro constant, NA = 6.02  1023 mol1 gravitational constant, G = 6.67  1011 N m2 kg2 acceleration of free fall, g = 9.81 m s2 Formulae uniformly accelerated motion, s = ut + 1 2 at2 v2 = u2 + 2as resistors in series, R = R1 + R2 + . . . resistors in parallel, 1/R = 1/R1 + 1/R2 + . . .

3 [Turn over Section A Answer ALL questions in this section. 1 (a) A student writes down the following equation to describe the forces acting on a sphere falling under gravity through a medium of liquid,   2 3 L 46 3rv r g     whereby r is the radius of the sphere, v the velocity, g the acceleration of free fall,  the coefficient of viscosity of the liquid with units: kg m−1 s−1,  and L the densities of the sphere and the liquid respectively. By checking the homogeneity of the equation, deduce whether the equation is correct. [2] L2   2 3 L 46 3rv r g     Units of left hand side: (kg m−1 s−1) (m) (m s−1)2 = (kg m2 s−3) Units of right hand side: (m3) (kg m−3) (m s−2) = (kg m s−2) Since the units on left and right hand sides are not equal, the equation is not correct. M1 A1 (b) Th